Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
75
81
85
89
Answer: Option
Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number = 551 = 19;    Third number = 1073 = 37.
29 29

Required sum = (19 + 29 + 37) = 85.

Discussion:
53 comments Page 4 of 6.

Rudrika said:   9 years ago
@Ashutosh,

Your explanation is very nice.

Krishna said:   9 years ago
@Jyoti, Can you explain it clearly?

Mahi said:   9 years ago
Good and clear explanation @Ashutosh.

Samir said:   9 years ago
Why we divide 29 from 551 & 1073?

Aby said:   9 years ago
Thank you, @Ashutosh.

Neharika said:   9 years ago
Four prime numbers are arranged in ascending order according to their magnitude. The product of first Three is 20,677 and the product of last three 33,263. Find the numbers.

Can anyone solve and explain this question ?

Jyoti. said:   9 years ago
@Sujeeth

1*3 = 3
5*7 = 35
5*0 = 0
1.
= 3 - 35 - 0 - 1.
= 28 - 0 - 1.
= 28 + 1.
= 29.

Soni said:   9 years ago
Please, explain the problem clearly.

Sujeeth said:   1 decade ago
Explain how 29 came?

Sathiya priya said:   1 decade ago
Let assume three numbers are a, b and c.

Given:

The product of a and b is 551.

The product of b and c is 1073.

b is common in both the product

b = H.C.F. of 551 and 1073 = 29;

a = (551/29) = 19.
c = (1073/289) = 37.

The sum of three number is 85.


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