Aptitude - Problems on H.C.F and L.C.M
Exercise : Problems on H.C.F and L.C.M - General Questions
- Problems on H.C.F and L.C.M - Formulas
- Problems on H.C.F and L.C.M - General Questions
21.
The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:
Answer: Option
Explanation:
Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm.
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
| First number = |  |
551 |  |
= 19; Third number = | |
1073 | |
= 37. |
| 29 | 29 |
Required sum = (19 + 29 + 37) = 85.
23.
Find the highest common factor of 36 and 84.
Answer: Option
Explanation:
36 = 22 x 32
84 = 22 x 3 x 7
H.C.F. = 22 x 3 = 12.
24.
Which of the following fraction is the largest ?
Answer: Option
Explanation:
L.C.M. of 8, 16, 40 and 80 = 80.
| 7 | = | 70 | ; | 13 | = | 65 | ; | 31 | = | 62 |
| 8 | 80 | 16 | 80 | 40 | 80 |
| Since, | 70 | > | 65 | > | 63 | > | 62 | , so | 7 | > | 13 | > | 63 | > | 31 |
| 80 | 80 | 80 | 80 | 8 | 16 | 80 | 40 |
| So, | 7 | is the largest. |
| 8 |
25.
The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:
Answer: Option
Explanation:
Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.
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