Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
75
81
85
89
Answer: Option
Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.

Also, the given two products have the middle number in common.

So, middle number = H.C.F. of 551 and 1073 = 29;

First number = 551 = 19;    Third number = 1073 = 37.
29 29

Required sum = (19 + 29 + 37) = 85.

Discussion:
53 comments Page 1 of 6.

Ayush said:   3 months ago
Agree C is the correct answer.

Priya said:   4 years ago
Really Awesome explanation, Thanks @Aparna.
(2)

Priya said:   4 years ago
Really Awesome explanation, Thanks @Aparna.
(2)

Sarang Parmar said:   4 years ago
Thanks all.

Mouni said:   4 years ago
HCF of 551 and 1073 = 29 + 19 + 27 = 85.

Anvi said:   4 years ago
Why we use HCF ? Explain clearly.
(3)

Riteeka said:   4 years ago
Hey @Satyajit.

Your method is perfect. Helped a lot. Thank you.
(2)

Satyajit said:   5 years ago
To find hcf of big no:

1073/551=1,rem=522
Then 551/522=1,rem=29.
Then 522/29=18,rem=0.
So HCF=29.
(18)

Nivi said:   5 years ago
Let me explain.

Co-prime : factors are 1 and itself.

Given: XY=551.
YZ=1073.

Since why is a common factor in both the equations and the as the no's are caprice then the other factor becomes the highest common factor.

So, Y is the HCF of XY and YZ.
(7)

Shreya said:   6 years ago
I don't understand why we take the HCF of 551 and 1073.
(6)


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