Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
| First number = |  |
551 |  |
= 19; Third number = | |
1073 | |
= 37. |
| 29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 6 of 6.
Vishnu said:
1 decade ago
Awesome way of explaining :-)
Aparna said:
1 decade ago
Nothing to worry,
see in HCF we get a number which is common to both numbers.
So find the hcf of 551 and 1073, we get 29
which is one number among three nos.
Let other two numbers be a and b
Given
a*29=551
a=551/29
a=19
Now,
b*29=1073
b=37
Hence three numbers. are 29,19,37
see in HCF we get a number which is common to both numbers.
So find the hcf of 551 and 1073, we get 29
which is one number among three nos.
Let other two numbers be a and b
Given
a*29=551
a=551/29
a=19
Now,
b*29=1073
b=37
Hence three numbers. are 29,19,37
(16)
Anjali said:
1 decade ago
I didn't understand this question. Please help me.
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