Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
| First number = |  |
551 |  |
= 19; Third number = | |
1073 | |
= 37. |
| 29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 5 of 6.
Prathyusha.j said:
1 decade ago
@Gopi.
If we take the numbers to be 23 and 31,
We get 23*29=667.. which is in contrast with the question.
So the numbers should be 19 and 37.
If we take the numbers to be 23 and 31,
We get 23*29=667.. which is in contrast with the question.
So the numbers should be 19 and 37.
Venkatareddy said:
1 decade ago
How the you can say 29 is the common factor and explain?
Gopi said:
1 decade ago
In-case of co primes, if 29 is the middle number then first should be 23 and last should be 31. Then the given values not match. Please clarify.
Mustafa Ahmed said:
1 decade ago
How to find 29? Please show the divided process.
Rahul said:
1 decade ago
Can any one tell me how to calculate HCF/LCM of big numbers in easy way?
Ashutosh said:
1 decade ago
Hello friends its simple to get 29.
1 step:-1073-551 we will get 522.
Now,
2 step:- 551-522 we will get 29
1 step:-1073-551 we will get 522.
Now,
2 step:- 551-522 we will get 29
Prasant said:
1 decade ago
How to find 29 ? Is there any shortest way?
Sangeeta said:
1 decade ago
How to know that 29 is the common factor?
Please tell me?
Please tell me?
Vinayak said:
1 decade ago
@uttam. You are right.
Uttam said:
1 decade ago
Consider numbers as X, Y, Z respectively.
Now,
Consider product XY = 551 ------eq1
Consider product YZ = 1073 -----eq2
So,clearly common highest factor btw XY and YZ should be Y
i.e HCF (551,1073) = 29.
From eq 1, X=19.
from eq 2, Y=37.
Pls comment if my assumption is wrong.
Now,
Consider product XY = 551 ------eq1
Consider product YZ = 1073 -----eq2
So,clearly common highest factor btw XY and YZ should be Y
i.e HCF (551,1073) = 29.
From eq 1, X=19.
from eq 2, Y=37.
Pls comment if my assumption is wrong.
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