Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 22)
22.
Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
Answer: Option
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
| First number = |  |
551 |  |
= 19; Third number = | |
1073 | |
= 37. |
| 29 | 29 |
Required sum = (19 + 29 + 37) = 85.
Discussion:
53 comments Page 3 of 6.
Divyanshu Priyadarshi said:
8 years ago
Let the three numbers be x, y and z.
Hence, xy=551 and yz=1073.
Middle number =HCF of 551 and 1073 = 29.
First number =551/29= 19.
Third number =1073/29= 37.
Required numbers are 19,29 and 37.
Hence, xy=551 and yz=1073.
Middle number =HCF of 551 and 1073 = 29.
First number =551/29= 19.
Third number =1073/29= 37.
Required numbers are 19,29 and 37.
Ajit said:
8 years ago
Let me explain (551-1071) = 522 then again least no minus (551-522) = 29.
Diksha said:
9 years ago
Why the 29 divided the term. It's middle term but what logic behind this?
Purva said:
9 years ago
@Tanvir.
2497/60 we get remainder as 37.
Now: LCM of 5, 6, 4, 3 is 60.
(60 - 37) = 23.
2497/60 we get remainder as 37.
Now: LCM of 5, 6, 4, 3 is 60.
(60 - 37) = 23.
Tanvir said:
9 years ago
Which least number should be added to 2497 so that the sum is exactly divisible by 3, 4, 5, and 6?
Solve it and find the answer.
Solve it and find the answer.
Anonymous said:
9 years ago
How will the solution change if the given numbers are not co-prime?
Ram said:
9 years ago
29 is the HCF of 551 and 1073.
To find HCF of 551 and 1073 follow these steps.
551)1071(1
551
----------------
522)551(1
522
------------
29)522(18
29
---------
232
232
------------
XXX
So,HCF of 551 and 1073 is 29.
To find HCF of 551 and 1073 follow these steps.
551)1071(1
551
----------------
522)551(1
522
------------
29)522(18
29
---------
232
232
------------
XXX
So,HCF of 551 and 1073 is 29.
Preethi said:
9 years ago
I can't understand how 29 comes?
Ranjith said:
9 years ago
xy = 551 & yz = 1073; clearly y is a HCF.
Multiply xy * yz = 1073 * 551 we get xzy^2 = 29sqroot703;
So 29 is y; then it is easy to proceed .
Multiply xy * yz = 1073 * 551 we get xzy^2 = 29sqroot703;
So 29 is y; then it is easy to proceed .
(1)
Anant said:
9 years ago
Thanks @Ashutosh.
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