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Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
Problems on Ages
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
2  1 times
2
2  3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 31 of 32.
Akshay said:   6 years ago
How 48/24 came?

Please tell me.
Priya said:   5 years ago
Why we are adding the 16 in the step 4x+16/x+16, sir.

4x+16/x+16 how to get this step. Please explain sir.
Stark said:   5 years ago
I got the answer as two and one-fifth times.
Pratheeksha said:   5 years ago
How 5/2? Can anyone explain.
Manmeet said:   5 years ago
The answer should be 2.5.
Neha said:   5 years ago
Let's Ronit present age be x.
Father's present age =3x.
After 8 yrs,
Ronits age = x+8.
Fathers age =3x+8.
3x+8=2.5(x+8)
X=24yrs.

Fathers age = 3x =3*24=72yrs
After a further 8 yrs,
Fathers age =72+8=80yrs,
Ronit's age=24+8=32yrs.
No.of times father age to Ronit age =80/32.
Then we get 2.5times(ans).
Pratiksha said:   5 years ago
@All.

Here father age is 3times so the last equation is wrong.
Rebecca said:   5 years ago
Why do we have to add 8 to 5/2 of x yet it was after 8 years?

So, 4x+8 =5x/2.
Shubham Londhe said:   5 years ago
It's only said his age would be 2.5 times of son's age after 8 years.

So only 2.5 * X seems logical. Why 2.5(X+8)? Explain it.
Gauri_ said:   5 years ago
Why 16 is added? Explain in detail.
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