Aptitude - Problems on Ages - Discussion

A) 2 and a half times old= 2 1/2 = (2*2+1)/2 = 5/2.

B) Initially father is 3 times son's age.
After 8 years father is 2 1/2 times the son's age.
Again after 8 years father is? Times sons age?

Therefore, 0+8+8= 16.

Hence the equation 4x + 16/ x+ 16.

Can someone please tell me how?

=> (4x+8) =5x+40 Became
=> 8x+16?

I really didn't understand this part. Anyone help me to get it.

At present, F and R.

R=R,

Father's age would 3 times more than Ronit's age
F=3R+R -> F=4R -----> (1)

After 8 years, F+8 and R+8.

Father would be 2 and half a times of Ronit's age
F+8=2 1/2(R+8).

Mixed fraction 2 1/2 = ((2*2)+1)/2 = 5/2.
F + 8=5/2(R+8),
2F+16 = 5R + 40,
2F-5R = 40 - 16,
2F-5R = 24 -------> (2)

Sub F=4R in (2).
2(4R)-5R = 24,
8R-5R = 24,
3R= 24.
R = 8 years, F = 32 years.
After further 8 years means;
F + 16 = 32 + 16= 48,
R + 16 = 8 + 16= 24,
Required ratio= 48/24 = 2.
Hence, After further 8 years, 2 times he would be of Ronit's age.

If we will take Rohit's age I think it should be 3x (x+3).
If we will take Rohit's age as 1 it can be 4 only.

Correct me, If I am wrong.

@All.

Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?

Because when any question ask father is 5 times of son then we put father is 5x and son is x.

Anyone, please explain this.

Anyone, Can you explain this sum by taking 2.5?

If we take 2.5 or 5/2 will we get the same answer? Anyone explain.

It should be 3x + 8 = 5/2 (x+8).

It should be 3x + 8 = 5/2 (x+8).

The right answer is 3.

At first it is;
1 : 4.

then;
2 : 5.

Here difference after 8 years is 1.
1 part = 8 years.

Again we increase 8 years;
3 : 6.