Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
![]() |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
326 comments Page 1 of 33.
Yella Subba Pragada Rao said:
3 weeks ago
4X+8 = (X+8) * 2.5,
4X+8 = 2.5X + 20,
1.5X = 12,
X = 8
If X=8, Then Father age is 32 (Four times X)
Now, After Eight years Ronith age is 16, Father age is 40 which is 2.5 times of Ronith age.
Later, After further Eight years Ronith age is 24, Father age is 48.
That means Father age is Two times of Ronith age.
So Answer is Option A) 2 times.
4X+8 = 2.5X + 20,
1.5X = 12,
X = 8
If X=8, Then Father age is 32 (Four times X)
Now, After Eight years Ronith age is 16, Father age is 40 which is 2.5 times of Ronith age.
Later, After further Eight years Ronith age is 24, Father age is 48.
That means Father age is Two times of Ronith age.
So Answer is Option A) 2 times.
Pranali said:
2 months ago
Yes, I agree with you @Janarthanan.
(1)
SumitPandey said:
2 months ago
@All.
Here is the trick to solve this;
Father : Son.
4 : 1.
And +8 years, according to the question, it becomes 5/2.
So,
5 : 2.
And again 8 years. So in the above ration there is 1 increment in 8 year it means for the next 8 year 1 more increament then we get.
6 : 3 which is = 2(Ans).
Here is the trick to solve this;
Father : Son.
4 : 1.
And +8 years, according to the question, it becomes 5/2.
So,
5 : 2.
And again 8 years. So in the above ration there is 1 increment in 8 year it means for the next 8 year 1 more increament then we get.
6 : 3 which is = 2(Ans).
(13)
Aswini kumar Jena said:
4 months ago
How to add 8 more in a 16 ratio?
(3)
Ayush Pandey said:
5 months ago
Very clear, thanks all for explaining the answer.
(1)
Kolimi said:
5 months ago
Present ages F : S = 4:1(because father is 3 times more than son which is 4-1 =3)
Father = 4R.
Son = R.
After 8 years
F: S = 2.5 : 1.
(4R + 8)(R+8) = 2.5
4R + 8 = 2.5(R + 8),
4R + 8 = 2.5R + 20,
4R - 2.5R = 20 - 8.
1.5R = 12.
R=12/1.5 = 8.
If R is 8 then 4R is 4(8)= 32, that is, father's age after 8 years.
So, after 16(that is, after 8 years + after 8 years).
F = 32 + 16 = 48.
S = 8 + 16 = 24.
F:S = 48:24 = 2:1.
That is Father's age 2 times more than son after another 8 years.
Father = 4R.
Son = R.
After 8 years
F: S = 2.5 : 1.
(4R + 8)(R+8) = 2.5
4R + 8 = 2.5(R + 8),
4R + 8 = 2.5R + 20,
4R - 2.5R = 20 - 8.
1.5R = 12.
R=12/1.5 = 8.
If R is 8 then 4R is 4(8)= 32, that is, father's age after 8 years.
So, after 16(that is, after 8 years + after 8 years).
F = 32 + 16 = 48.
S = 8 + 16 = 24.
F:S = 48:24 = 2:1.
That is Father's age 2 times more than son after another 8 years.
(3)
Prateek said:
7 months ago
4x + 8 = 2.5x + 20.
1.5x = 12,
x = 12/1.5
x = 8.
24/48 = 1/2.
1.5x = 12,
x = 12/1.5
x = 8.
24/48 = 1/2.
(1)
Rakesh said:
11 months ago
@All.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
(12)
Janarthanan said:
1 year ago
@All.
My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?
Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?
Anyone, explain this to me.
My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?
Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?
Anyone, explain this to me.
(62)
Watson said:
1 year ago
He would be 2 (1/2) times of Ronit's age.
2 1/2 which is a mixed fraction. So it is written as [ (2*2) +1]/2 = 5/2.
2 1/2 which is a mixed fraction. So it is written as [ (2*2) +1]/2 = 5/2.
(12)
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