Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
325 comments Page 1 of 33.

Pranali said:   14 hours ago
Yes, I agree with you @Janarthanan.

SumitPandey said:   2 weeks ago
@All.

Here is the trick to solve this;
Father : Son.
4 : 1.
And +8 years, according to the question, it becomes 5/2.
So,
5 : 2.
And again 8 years. So in the above ration there is 1 increment in 8 year it means for the next 8 year 1 more increament then we get.
6 : 3 which is = 2(Ans).
(4)

Aswini kumar Jena said:   2 months ago
How to add 8 more in a 16 ratio?
(2)

Ayush Pandey said:   3 months ago
Very clear, thanks all for explaining the answer.
(1)

Kolimi said:   4 months ago
Present ages F : S = 4:1(because father is 3 times more than son which is 4-1 =3)
Father = 4R.
Son = R.

After 8 years
F: S = 2.5 : 1.

(4R + 8)(R+8) = 2.5
4R + 8 = 2.5(R + 8),
4R + 8 = 2.5R + 20,
4R - 2.5R = 20 - 8.
1.5R = 12.
R=12/1.5 = 8.
If R is 8 then 4R is 4(8)= 32, that is, father's age after 8 years.
So, after 16(that is, after 8 years + after 8 years).
F = 32 + 16 = 48.
S = 8 + 16 = 24.
F:S = 48:24 = 2:1.
That is Father's age 2 times more than son after another 8 years.
(3)

Prateek said:   6 months ago
4x + 8 = 2.5x + 20.
1.5x = 12,
x = 12/1.5
x = 8.
24/48 = 1/2.
(1)

Rakesh said:   9 months ago
@All.
Simply;
Ronith's present age = x.
Father's age=3 times more than Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years:
Now we are in the present stage, so they have asked for a further 8 years,
So, a further 8 years and an additional 8 years =16 years.
=> 4x + 16/x + 16+2.
(12)

Janarthanan said:   11 months ago
@All.

My doubt is; in the question, it is given "Father has aged 3times the son" then how father's age will be x + 3x = 4x? If 4x is father age then it will become wrong. right?

Ex. Let son age be 2 years, father age will be 8years (4x, as given in explanation). Then how it will be correct?

Anyone, explain this to me.
(60)

Watson said:   12 months ago
He would be 2 (1/2) times of Ronit's age.

2 1/2 which is a mixed fraction. So it is written as [ (2*2) +1]/2 = 5/2.
(12)

Honey said:   1 year ago
Ronith's present age = x.
Father's age=3 times more of Ronith's age.
So, x + 3x = 4x.
So, after 8 years, 4x + 8 = 5/2(x+8) by doing the calculation we will x = 8.
Further 8 years: Now we are in the present stage, so they have asked for a further 8 years, so future 8 years and a further 8 years =16 years.
=> 4x + 16/x + 16+2.
(11)


Post your comments here:

Your comments will be displayed after verification.