Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 2 of 32.
Mohit patil said:
1 year ago
How come 16 here? Anyone, Explain to me.
(8)
Vaibhav said:
1 year ago
@All.
This question is a tricky one, as it states Father's age is three times more than Ronit's age. The "times" would imply F=3R but it also has a "more" statement. Meaning that Father's age is what adds to 3 times Ronit's age to Ronit's age, which means.
F = 3R+R.
This question is a tricky one, as it states Father's age is three times more than Ronit's age. The "times" would imply F=3R but it also has a "more" statement. Meaning that Father's age is what adds to 3 times Ronit's age to Ronit's age, which means.
F = 3R+R.
(48)
Rajdip Kumar Dora said:
1 year ago
How it's 16 years? Can anyone please explain?
(5)
Unknown said:
1 year ago
How ratio be calculated in this question? Please explain to me.
(3)
Abhishek Zatakiya said:
1 year ago
Let son age = x.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
(31)
Mani said:
2 years ago
In the question, son's age is 2 (1/2) age.
So, 2x1/2 is 5/2fraction form.
So, 2x1/2 is 5/2fraction form.
(18)
Ganesh Lokhande said:
2 years ago
Why 5/2 is used? Please explain to me.
(29)
Villasnjsjs said:
2 years ago
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
(11)
Naveen said:
2 years ago
F:S
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
(16)
Petchi Raja said:
2 years ago
Father aged 3 times more than his son Ronit", everyone would think Father's age is triple of Son's age, right?
How to assume this? Anyone, please explain me clearly.
How to assume this? Anyone, please explain me clearly.
(54)
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