Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 3 of 32.
Karthik said:
2 years ago
x = 3+y,
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
(9)
Shailesh Gupta said:
2 years ago
@All.
The correct answer is B.
Here is the explanation for the solution:
Let's first represent Ronit's current age as "R" and Father's current age as "F."
According to the information provided:
1. Father's age is three times more than Ronit's age: F = 3R
2. After 8 years, Father's age would be two and a half times Ronit's age: F + 8 = 2.5 * (R + 8)
Now, let's solve the equations to find the current ages of Ronit and his Father:
From equation 1, we have F = 3R
Substitute this value of F in equation 2:
3R + 8 = 2.5 * (R + 8)
Now, let's solve for R:
3R + 8 = 2.5R + 20,
3R - 2.5R = 20 - 8
0.5R = 12,
R = 12/0.5.
R = 24.
Now that we know Ronit's current age (R = 24), we can find Father's current age using equation 1:
F = 3R.
F = 3 * 24.
F = 72.
After further 8 years, Ronit's age will be:
Ronit's age after 8 years = R + 8 = 24 + 8 = 32.
Father's age after 8 years will be:
Father's age after 8 years = F + 8 = 72 + 8 = 80.
Now, let's find out how many times Father's age will be of Ronit's age after further 8 years:
(Father's age after further 8 years)/(Ronit's age after further 8 years) = 80/32 = 2.5.
After a further 8 years, Father's age will be 2.5 times Ronit's age.
The correct answer is B.
Here is the explanation for the solution:
Let's first represent Ronit's current age as "R" and Father's current age as "F."
According to the information provided:
1. Father's age is three times more than Ronit's age: F = 3R
2. After 8 years, Father's age would be two and a half times Ronit's age: F + 8 = 2.5 * (R + 8)
Now, let's solve the equations to find the current ages of Ronit and his Father:
From equation 1, we have F = 3R
Substitute this value of F in equation 2:
3R + 8 = 2.5 * (R + 8)
Now, let's solve for R:
3R + 8 = 2.5R + 20,
3R - 2.5R = 20 - 8
0.5R = 12,
R = 12/0.5.
R = 24.
Now that we know Ronit's current age (R = 24), we can find Father's current age using equation 1:
F = 3R.
F = 3 * 24.
F = 72.
After further 8 years, Ronit's age will be:
Ronit's age after 8 years = R + 8 = 24 + 8 = 32.
Father's age after 8 years will be:
Father's age after 8 years = F + 8 = 72 + 8 = 80.
Now, let's find out how many times Father's age will be of Ronit's age after further 8 years:
(Father's age after further 8 years)/(Ronit's age after further 8 years) = 80/32 = 2.5.
After a further 8 years, Father's age will be 2.5 times Ronit's age.
(83)
Chandni negi said:
2 years ago
As someone has doubts on 5/2.
As it is mentioned in the question, the father would be (two and a half time's) Ronit's age.
So, it is in the form of a mixed fraction.
We write one and a half is 1/2
So 2 and a half is = 2 1/2,
So, 2*2+1/2,
= 5/2.
As it is mentioned in the question, the father would be (two and a half time's) Ronit's age.
So, it is in the form of a mixed fraction.
We write one and a half is 1/2
So 2 and a half is = 2 1/2,
So, 2*2+1/2,
= 5/2.
(34)
Amey said:
2 years ago
@All.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
(15)
Madhu said:
2 years ago
Why 5/2 is used? Please explain to me.
(13)
Conrad Lynn said:
2 years ago
Why 5/2 is used? Please explain me.
(9)
Siva said:
2 years ago
Let's assume the current age of Ronit is R years. According to the problem, the father's age is three times that of Ronit's age.
Therefore, the current age of the father is 3R years.
After 8 years, Ronit's age will be R + 8 years, and the father's age will be 3R + 8 years.
According to the problem, the father's age will be two and a half times Ronit's age at that time. we can write:
3R + 8 = 2.5(R + 8).
Let's solve this equation to find Ronit's current age:
3R + 8 = 2.5R + 20.
0.5R = 12,
R = 24.
Therefore, Ronit's current age is 24 years. Consequently, the father's current age is 3R = 3 * 24 = 72 years.
After another 8 years, Ronit's age will be 24 + 8 = 32 years, and the father's age will be 72 + 8 = 80 years.
To find out how many times the father's age is of Ronit's age at that time, we divide the father's age by Ronit's age:
80/32 = 2.5
Therefore, after a further 8 years, the father will be 2.5 times Ronit's age.
Therefore, the current age of the father is 3R years.
After 8 years, Ronit's age will be R + 8 years, and the father's age will be 3R + 8 years.
According to the problem, the father's age will be two and a half times Ronit's age at that time. we can write:
3R + 8 = 2.5(R + 8).
Let's solve this equation to find Ronit's current age:
3R + 8 = 2.5R + 20.
0.5R = 12,
R = 24.
Therefore, Ronit's current age is 24 years. Consequently, the father's current age is 3R = 3 * 24 = 72 years.
After another 8 years, Ronit's age will be 24 + 8 = 32 years, and the father's age will be 72 + 8 = 80 years.
To find out how many times the father's age is of Ronit's age at that time, we divide the father's age by Ronit's age:
80/32 = 2.5
Therefore, after a further 8 years, the father will be 2.5 times Ronit's age.
(44)
Dhaval said:
2 years ago
Father (F) = 3S (son).
After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.
After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.
After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
(12)
Lokesh said:
2 years ago
As per the question, Father's age is 3 times more than the sons age.
Not 3 times of son's age..
That's why here is 3x+x.
Sons present age is = x
Father present age is = x+3x= 4x
After 8 years father's age would be -
4x+8 = 5/2(x+8).
By solving we get x=8,
now son's present age is x=8.
Father's age is 4x = 4*8= 32.
The required ratio 32+16/8+16 = 48/24 = 2 ans.
Not 3 times of son's age..
That's why here is 3x+x.
Sons present age is = x
Father present age is = x+3x= 4x
After 8 years father's age would be -
4x+8 = 5/2(x+8).
By solving we get x=8,
now son's present age is x=8.
Father's age is 4x = 4*8= 32.
The required ratio 32+16/8+16 = 48/24 = 2 ans.
(24)
Kamleshkumar said:
2 years ago
Say Sons age is X;
F = 3X
3X + 8 = 5/2(X+8).
6X + 16 = 5X+40.
X = 40 - 16,
X = 24.
So, 3X+16/X+16.
= 3 * 24+16/24+16.
= 88/40.
= 2.2.
Means -> 2 1/5.
F = 3X
3X + 8 = 5/2(X+8).
6X + 16 = 5X+40.
X = 40 - 16,
X = 24.
So, 3X+16/X+16.
= 3 * 24+16/24+16.
= 88/40.
= 2.2.
Means -> 2 1/5.
(18)
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