Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
![]() |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 3 of 33.
Villasnjsjs said:
2 years ago
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
(11)
Naveen said:
2 years ago
F:S
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
(16)
Petchi Raja said:
2 years ago
Father aged 3 times more than his son Ronit", everyone would think Father's age is triple of Son's age, right?
How to assume this? Anyone, please explain me clearly.
How to assume this? Anyone, please explain me clearly.
(54)
Karthik said:
2 years ago
x = 3+y,
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
(9)
Shailesh Gupta said:
2 years ago
@All.
The correct answer is B.
Here is the explanation for the solution:
Let's first represent Ronit's current age as "R" and Father's current age as "F."
According to the information provided:
1. Father's age is three times more than Ronit's age: F = 3R
2. After 8 years, Father's age would be two and a half times Ronit's age: F + 8 = 2.5 * (R + 8)
Now, let's solve the equations to find the current ages of Ronit and his Father:
From equation 1, we have F = 3R
Substitute this value of F in equation 2:
3R + 8 = 2.5 * (R + 8)
Now, let's solve for R:
3R + 8 = 2.5R + 20,
3R - 2.5R = 20 - 8
0.5R = 12,
R = 12/0.5.
R = 24.
Now that we know Ronit's current age (R = 24), we can find Father's current age using equation 1:
F = 3R.
F = 3 * 24.
F = 72.
After further 8 years, Ronit's age will be:
Ronit's age after 8 years = R + 8 = 24 + 8 = 32.
Father's age after 8 years will be:
Father's age after 8 years = F + 8 = 72 + 8 = 80.
Now, let's find out how many times Father's age will be of Ronit's age after further 8 years:
(Father's age after further 8 years)/(Ronit's age after further 8 years) = 80/32 = 2.5.
After a further 8 years, Father's age will be 2.5 times Ronit's age.
The correct answer is B.
Here is the explanation for the solution:
Let's first represent Ronit's current age as "R" and Father's current age as "F."
According to the information provided:
1. Father's age is three times more than Ronit's age: F = 3R
2. After 8 years, Father's age would be two and a half times Ronit's age: F + 8 = 2.5 * (R + 8)
Now, let's solve the equations to find the current ages of Ronit and his Father:
From equation 1, we have F = 3R
Substitute this value of F in equation 2:
3R + 8 = 2.5 * (R + 8)
Now, let's solve for R:
3R + 8 = 2.5R + 20,
3R - 2.5R = 20 - 8
0.5R = 12,
R = 12/0.5.
R = 24.
Now that we know Ronit's current age (R = 24), we can find Father's current age using equation 1:
F = 3R.
F = 3 * 24.
F = 72.
After further 8 years, Ronit's age will be:
Ronit's age after 8 years = R + 8 = 24 + 8 = 32.
Father's age after 8 years will be:
Father's age after 8 years = F + 8 = 72 + 8 = 80.
Now, let's find out how many times Father's age will be of Ronit's age after further 8 years:
(Father's age after further 8 years)/(Ronit's age after further 8 years) = 80/32 = 2.5.
After a further 8 years, Father's age will be 2.5 times Ronit's age.
(83)
Chandni negi said:
2 years ago
As someone has doubts on 5/2.
As it is mentioned in the question, the father would be (two and a half time's) Ronit's age.
So, it is in the form of a mixed fraction.
We write one and a half is 1/2
So 2 and a half is = 2 1/2,
So, 2*2+1/2,
= 5/2.
As it is mentioned in the question, the father would be (two and a half time's) Ronit's age.
So, it is in the form of a mixed fraction.
We write one and a half is 1/2
So 2 and a half is = 2 1/2,
So, 2*2+1/2,
= 5/2.
(34)
Amey said:
2 years ago
@All.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
(15)
Madhu said:
2 years ago
Why 5/2 is used? Please explain to me.
(13)
Conrad Lynn said:
2 years ago
Why 5/2 is used? Please explain me.
(9)
Siva said:
2 years ago
Let's assume the current age of Ronit is R years. According to the problem, the father's age is three times that of Ronit's age.
Therefore, the current age of the father is 3R years.
After 8 years, Ronit's age will be R + 8 years, and the father's age will be 3R + 8 years.
According to the problem, the father's age will be two and a half times Ronit's age at that time. we can write:
3R + 8 = 2.5(R + 8).
Let's solve this equation to find Ronit's current age:
3R + 8 = 2.5R + 20.
0.5R = 12,
R = 24.
Therefore, Ronit's current age is 24 years. Consequently, the father's current age is 3R = 3 * 24 = 72 years.
After another 8 years, Ronit's age will be 24 + 8 = 32 years, and the father's age will be 72 + 8 = 80 years.
To find out how many times the father's age is of Ronit's age at that time, we divide the father's age by Ronit's age:
80/32 = 2.5
Therefore, after a further 8 years, the father will be 2.5 times Ronit's age.
Therefore, the current age of the father is 3R years.
After 8 years, Ronit's age will be R + 8 years, and the father's age will be 3R + 8 years.
According to the problem, the father's age will be two and a half times Ronit's age at that time. we can write:
3R + 8 = 2.5(R + 8).
Let's solve this equation to find Ronit's current age:
3R + 8 = 2.5R + 20.
0.5R = 12,
R = 24.
Therefore, Ronit's current age is 24 years. Consequently, the father's current age is 3R = 3 * 24 = 72 years.
After another 8 years, Ronit's age will be 24 + 8 = 32 years, and the father's age will be 72 + 8 = 80 years.
To find out how many times the father's age is of Ronit's age at that time, we divide the father's age by Ronit's age:
80/32 = 2.5
Therefore, after a further 8 years, the father will be 2.5 times Ronit's age.
(44)
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