Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
![]() |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
325 comments Page 3 of 33.
Abhishek Zatakiya said:
2 years ago
Let son age = x.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
(31)
Mani said:
2 years ago
In the question, son's age is 2 (1/2) age.
So, 2x1/2 is 5/2fraction form.
So, 2x1/2 is 5/2fraction form.
(18)
Ganesh Lokhande said:
2 years ago
Why 5/2 is used? Please explain to me.
(29)
Villasnjsjs said:
2 years ago
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
(11)
Naveen said:
2 years ago
F:S
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
(16)
Petchi Raja said:
2 years ago
Father aged 3 times more than his son Ronit", everyone would think Father's age is triple of Son's age, right?
How to assume this? Anyone, please explain me clearly.
How to assume this? Anyone, please explain me clearly.
(54)
Karthik said:
3 years ago
x = 3+y,
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
x = 5/2y,
5/2 = 3+y,
y = 5/2 - 3.
y = 2.5.
(9)
Shailesh Gupta said:
3 years ago
@All.
The correct answer is B.
Here is the explanation for the solution:
Let's first represent Ronit's current age as "R" and Father's current age as "F."
According to the information provided:
1. Father's age is three times more than Ronit's age: F = 3R
2. After 8 years, Father's age would be two and a half times Ronit's age: F + 8 = 2.5 * (R + 8)
Now, let's solve the equations to find the current ages of Ronit and his Father:
From equation 1, we have F = 3R
Substitute this value of F in equation 2:
3R + 8 = 2.5 * (R + 8)
Now, let's solve for R:
3R + 8 = 2.5R + 20,
3R - 2.5R = 20 - 8
0.5R = 12,
R = 12/0.5.
R = 24.
Now that we know Ronit's current age (R = 24), we can find Father's current age using equation 1:
F = 3R.
F = 3 * 24.
F = 72.
After further 8 years, Ronit's age will be:
Ronit's age after 8 years = R + 8 = 24 + 8 = 32.
Father's age after 8 years will be:
Father's age after 8 years = F + 8 = 72 + 8 = 80.
Now, let's find out how many times Father's age will be of Ronit's age after further 8 years:
(Father's age after further 8 years)/(Ronit's age after further 8 years) = 80/32 = 2.5.
After a further 8 years, Father's age will be 2.5 times Ronit's age.
The correct answer is B.
Here is the explanation for the solution:
Let's first represent Ronit's current age as "R" and Father's current age as "F."
According to the information provided:
1. Father's age is three times more than Ronit's age: F = 3R
2. After 8 years, Father's age would be two and a half times Ronit's age: F + 8 = 2.5 * (R + 8)
Now, let's solve the equations to find the current ages of Ronit and his Father:
From equation 1, we have F = 3R
Substitute this value of F in equation 2:
3R + 8 = 2.5 * (R + 8)
Now, let's solve for R:
3R + 8 = 2.5R + 20,
3R - 2.5R = 20 - 8
0.5R = 12,
R = 12/0.5.
R = 24.
Now that we know Ronit's current age (R = 24), we can find Father's current age using equation 1:
F = 3R.
F = 3 * 24.
F = 72.
After further 8 years, Ronit's age will be:
Ronit's age after 8 years = R + 8 = 24 + 8 = 32.
Father's age after 8 years will be:
Father's age after 8 years = F + 8 = 72 + 8 = 80.
Now, let's find out how many times Father's age will be of Ronit's age after further 8 years:
(Father's age after further 8 years)/(Ronit's age after further 8 years) = 80/32 = 2.5.
After a further 8 years, Father's age will be 2.5 times Ronit's age.
(83)
Chandni negi said:
3 years ago
As someone has doubts on 5/2.
As it is mentioned in the question, the father would be (two and a half time's) Ronit's age.
So, it is in the form of a mixed fraction.
We write one and a half is 1/2
So 2 and a half is = 2 1/2,
So, 2*2+1/2,
= 5/2.
As it is mentioned in the question, the father would be (two and a half time's) Ronit's age.
So, it is in the form of a mixed fraction.
We write one and a half is 1/2
So 2 and a half is = 2 1/2,
So, 2*2+1/2,
= 5/2.
(34)
Amey said:
3 years ago
@All.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
Here, If x = 8 then 3 times more is 24 which is the father's age and after 8 more years x = 16 and the father's age will be 32 which is not 2 and a half times 16..
So, 3x is correct and x + 3x is wrong.
So, the correct answer will be 2.5.
(15)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers
