Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
322 comments Page 4 of 33.

Dhaval said:   2 years ago
Father (F) = 3S (son).

After 8 year;
F + 8 = 5/2(S + 8)
Put F = 3S.

After Solution S = 24.
Now in the present time so before 8 year;
S =24 - 8 = 16.
Now F = 3S.
F = 3×16 = 48.
After further 8 years.
So, Father/son = 48/24.
Ans. 2.
(12)

Lokesh said:   3 years ago
As per the question, Father's age is 3 times more than the sons age.
Not 3 times of son's age..
That's why here is 3x+x.
Sons present age is = x
Father present age is = x+3x= 4x
After 8 years father's age would be -
4x+8 = 5/2(x+8).

By solving we get x=8,
now son's present age is x=8.
Father's age is 4x = 4*8= 32.

The required ratio 32+16/8+16 = 48/24 = 2 ans.
(24)

Kamleshkumar said:   3 years ago
Say Sons age is X;

F = 3X
3X + 8 = 5/2(X+8).
6X + 16 = 5X+40.
X = 40 - 16,
X = 24.

So, 3X+16/X+16.
= 3 * 24+16/24+16.
= 88/40.
= 2.2.
Means -> 2 1/5.
(18)

Bhavesh said:   3 years ago
A) 2 and a half times old= 2 1/2 = (2*2+1)/2 = 5/2.

B) Initially father is 3 times son's age.
After 8 years father is 2 1/2 times the son's age.
Again after 8 years father is? Times sons age?

Therefore, 0+8+8= 16.

Hence the equation 4x + 16/ x+ 16.
(14)

Vipul said:   3 years ago
Can someone please tell me how?

=> (4x+8) =5x+40 Became
=> 8x+16?

I really didn't understand this part. Anyone help me to get it.
(14)

L.Haritha said:   3 years ago
At present, F and R.

R=R,

Father's age would 3 times more than Ronit's age
F=3R+R -> F=4R -----> (1)

After 8 years, F+8 and R+8.

Father would be 2 and half a times of Ronit's age
F+8=2 1/2(R+8).

Mixed fraction 2 1/2 = ((2*2)+1)/2 = 5/2.
F + 8=5/2(R+8),
2F+16 = 5R + 40,
2F-5R = 40 - 16,
2F-5R = 24 -------> (2)

Sub F=4R in (2).
2(4R)-5R = 24,
8R-5R = 24,
3R= 24.
R = 8 years, F = 32 years.
After further 8 years means;
F + 16 = 32 + 16= 48,
R + 16 = 8 + 16= 24,
Required ratio= 48/24 = 2.
Hence, After further 8 years, 2 times he would be of Ronit's age.
(34)

Diksha said:   3 years ago
If we will take Rohit's age I think it should be 3x (x+3).
If we will take Rohit's age as 1 it can be 4 only.

Correct me, If I am wrong.
(7)

Hamza said:   3 years ago
@All.

Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?

Because when any question ask father is 5 times of son then we put father is 5x and son is x.

Anyone, please explain this.

Chinnu said:   3 years ago
Anyone, Can you explain this sum by taking 2.5?

Chinnu said:   3 years ago
If we take 2.5 or 5/2 will we get the same answer? Anyone explain.


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