Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 33 of 33.
Prateek said:
3 months ago
4x + 8 = 2.5x + 20.
1.5x = 12,
x = 12/1.5
x = 8.
24/48 = 1/2.
1.5x = 12,
x = 12/1.5
x = 8.
24/48 = 1/2.
Ayush Pandey said:
1 week ago
Very clear, thanks all for explaining the answer.
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