Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
326 comments Page 33 of 33.
Sree said:
5 years ago
Let Rohit age=X.
By condition:Fathers age=X + 3X,
After 8 yrs,
Fathers age=5/2(X+8).
So, 4x+8=5/2(x+8).
8x+16=5x+40.
X=8.
Sub x=8 in 5/2(x+8).
Ans:40.
After 8 yrs,
40+8=48.
Sons age present=8,
After 16 yrs, age=24,
24*2=48.
So, the answer is 3 times.
Thank you
By condition:Fathers age=X + 3X,
After 8 yrs,
Fathers age=5/2(X+8).
So, 4x+8=5/2(x+8).
8x+16=5x+40.
X=8.
Sub x=8 in 5/2(x+8).
Ans:40.
After 8 yrs,
40+8=48.
Sons age present=8,
After 16 yrs, age=24,
24*2=48.
So, the answer is 3 times.
Thank you
Gora4663 said:
5 years ago
Let son age = x
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Chinnu said:
4 years ago
If we take 2.5 or 5/2 will we get the same answer? Anyone explain.
Chinnu said:
4 years ago
Anyone, Can you explain this sum by taking 2.5?
Hamza said:
4 years ago
@All.
Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?
Because when any question ask father is 5 times of son then we put father is 5x and son is x.
Anyone, please explain this.
Please explain, father is two and a half mean 5/2. Then why we write 5/2 With son's age?
Because when any question ask father is 5 times of son then we put father is 5x and son is x.
Anyone, please explain this.
Yella Subba Pragada Rao said:
3 weeks ago
4X+8 = (X+8) * 2.5,
4X+8 = 2.5X + 20,
1.5X = 12,
X = 8
If X=8, Then Father age is 32 (Four times X)
Now, After Eight years Ronith age is 16, Father age is 40 which is 2.5 times of Ronith age.
Later, After further Eight years Ronith age is 24, Father age is 48.
That means Father age is Two times of Ronith age.
So Answer is Option A) 2 times.
4X+8 = 2.5X + 20,
1.5X = 12,
X = 8
If X=8, Then Father age is 32 (Four times X)
Now, After Eight years Ronith age is 16, Father age is 40 which is 2.5 times of Ronith age.
Later, After further Eight years Ronith age is 24, Father age is 48.
That means Father age is Two times of Ronith age.
So Answer is Option A) 2 times.
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