Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
![]() |
(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 30 of 32.
Swaraj said:
6 years ago
How 5/2 came? Can anyone explain.
Samanth kumar said:
6 years ago
How the ratio is 3:1?
It is 4:1 since in question it is clearly mentioned that "3 TIMES MORE THAN RONIT ".
Then only you'll get answer, never forget this if in question it says 3 times than another ratio will be 3:1, if it says 3 times more than or larger than other you should take 4:1.
It is 4:1 since in question it is clearly mentioned that "3 TIMES MORE THAN RONIT ".
Then only you'll get answer, never forget this if in question it says 3 times than another ratio will be 3:1, if it says 3 times more than or larger than other you should take 4:1.
Waghmare Jaydip said:
6 years ago
Hot come 5/2? Please tell me.
Rishi said:
6 years ago
Thanks for the explanation.
Tarunkumar Prajapati said:
6 years ago
Step 1: Father is aged three times more than his son Ronit.
Let's assume Son's Age as X,
Father's Age = X+3X = 4X.
Step 2. After 8 years, he would be two and a half times of Ronit's age.
4X+8 = 2.5(X+8),
4X+8 = 2.5X+20,
4X-2.5X = 20-8,
1.5X = 12.
X = 12/1.5.
X = 8.
So, Son's Age (X) = 8 and Father's Age 4X = 4(8) = 32 [We found the actual Age].
Now add 8 years: Son's Age = X+8 =8+8 =16 and Father's Age = 4X+8 =32+8 =40.
After a further 8 years, how many times would he be of Ronit's age?
Now add 8 years: Son's Age = 16+8 = 24 and Father's Age = 40+8 = 48.
So Correct answer is 2 times.
Let's assume Son's Age as X,
Father's Age = X+3X = 4X.
Step 2. After 8 years, he would be two and a half times of Ronit's age.
4X+8 = 2.5(X+8),
4X+8 = 2.5X+20,
4X-2.5X = 20-8,
1.5X = 12.
X = 12/1.5.
X = 8.
So, Son's Age (X) = 8 and Father's Age 4X = 4(8) = 32 [We found the actual Age].
Now add 8 years: Son's Age = X+8 =8+8 =16 and Father's Age = 4X+8 =32+8 =40.
After a further 8 years, how many times would he be of Ronit's age?
Now add 8 years: Son's Age = 16+8 = 24 and Father's Age = 40+8 = 48.
So Correct answer is 2 times.
Ashok said:
6 years ago
How you got ratio (4x+16)/(x+16)?
Can you explain the last step of ratio?
Can you explain the last step of ratio?
Waqas Raza said:
6 years ago
Couldn't understand (4x+16/ x+16) = 2? what's the logic behind this?
Janmaijay said:
6 years ago
How two and a half times can be written like 5/2 it must be 2/5?
Varun said:
6 years ago
Why we have to add x=8 ? I think we have to substitute the the value of x. Can anyone explain?
Dharanisree said:
6 years ago
How 5/2?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers