Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
326 comments Page 29 of 33.

John said:   8 years ago
How come 4x+16/x+16 = 48/24? Anyone explain me.

Prashant said:   8 years ago
How this ratio came into picture 4x+8?

Rohan said:   8 years ago
Can't we take 2.5 instead of 5/2?

Suhail said:   8 years ago
How comes 5/2? please explain.

Sharad said:   8 years ago
How last step 4x+16/x+16?

Saiganesh murarishetty said:   8 years ago
For every 8 years father's age decrease by halftime of his son's age so after further 8 years (5/2) - (1/2) =2 times.

Neethu said:   8 years ago
Let son age be x.

Father's age is 3 times more than son's age.
Which means x+3x=4x.
After 8years.
X+8=2 and half of x.

When we solve the equation we will get x as 8.
4x=32,

In the beginning of the question state that father's age is 3 times more than son age.
So x=8 then 3x=24.
After further 8years it becomes,
32+8=40.
3*8=24 and 5*8=40,
3-5=2.
and 2 times.

Venakta Narayana said:   8 years ago
As they said that father age is thrice,hence;

Let father present age = x,
Ronith age = y,

X = 3 * Y. => Y=X/3.

In the 2nd part, they mentioned that aftr 8yrs father age is 2.5 times of his son's age, hence
(X+8)=5/2(Y+8).

By substituting y=X/3, we get father present age i.e X=72yrs, Y=24yrs.

Then again he asked that how many times the difference between father and sons age further 8 yrs later;
Say later 8 yrs their difference is z. Hence
(X+8)=z(Y+8).

Putting X=72 and Y=24.
Then we get the difference is as z=2(approximately).

Santhiya said:   7 years ago
@All.

Simply, the solution is;

Given:

Ist father age= 3 times more than son age.
2nd after 8yrs father age= 2 1/2 times more than son age.
3rd after 8 yrs age =2 time more than son age.

Arjun said:   7 years ago
Father age can be taken as x.
Son age is taken as y.

According to the first statement, father age is three times more than sons age at present is x=3y

According to the second statement after 8 years father age is 8 times more than the two and a half age of son age.

2*1/2 can be written as 5/2.
So, x+8=5/2y.
Substitute x=3y,
3y+8=5/2y,
3y-5/2y=-8,
1/2y=-8.
y=-16 after 8 years.
After 8 years father age is twice than son age.
Then after 16 years also twice than son ager.


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