Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 25 of 32.
Arpitha said:
9 years ago
It's so simple!
The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.
The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.
Kavana said:
9 years ago
A is 2 years older than C and B is 2 years younger than C. The ratio of A's 6 years ago and B's 8 years ago is 6 : 5. Find C's present age.
COOLCALM said:
9 years ago
Father F and Rohit R.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
Vignesh said:
9 years ago
You can also solve this problem by taking son's age as x and father's age as y. First, y = 4x as it is 3 times 'more' than that of his son. Then after 8 years son's age will be x+8 and father's age will be y+8=5/2(x+8) after solving you will get x = 8 and y = 32. Then after 16 years let father be n times of son's age i.e y + 16 = n(x + 16).
or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.
Therefore father is 2 times his son's age after 16 years.
or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.
Therefore father is 2 times his son's age after 16 years.
Yalleswari said:
9 years ago
How required ratio 4x + 16/x + 16 come?
Ramesh said:
9 years ago
@Yalleswari.
As per the statement, x + 3x.
After 8 years, he would be 2 and a half times of his son.
So, x + 3x + 8 = x + 8.
4x + 8 = x + 8.
(4x + 8 ) = 5/2(x + 8).
We get, 8x + 16 = 5x + 40 => 3x = 24.
x = 8.
After further 8 years,
So add 8 to the equation 4x + 8 + 8 = x + 8+ 8.
4x + 16 = x + 16.
So the ratio is, (4x + 16)/(x + 16) = 48/24.
=> 2 years.
As per the statement, x + 3x.
After 8 years, he would be 2 and a half times of his son.
So, x + 3x + 8 = x + 8.
4x + 8 = x + 8.
(4x + 8 ) = 5/2(x + 8).
We get, 8x + 16 = 5x + 40 => 3x = 24.
x = 8.
After further 8 years,
So add 8 to the equation 4x + 8 + 8 = x + 8+ 8.
4x + 16 = x + 16.
So the ratio is, (4x + 16)/(x + 16) = 48/24.
=> 2 years.
Shushant mishra said:
9 years ago
Let the age of son be x then age of father will be 4x so we have ratio of father and son equals to 4x:x again after 8 years this becomes 5/2x:x as we all know that difference of age remains same then to make it same multiply above by 2 so that it becomes 5x:2x, therefore in 8 years 4x becomes 5x hence x is equal to 8 putting the value we get the age equal to 40 and 16 respectively and after 8 more years it will become 48 and 24 and hence father's age will be twice of son.
Rekha thakur said:
9 years ago
How you are getting 5/2?
Which has 1/2?
Which has 1/2?
Shushant mishra said:
9 years ago
@Rekha.
2 and half times means 5/2 times.
2 and half times means 5/2 times.
Nitesh kumar meena said:
9 years ago
Guys! It's three times more that mean 4x if it would be three times then we used 3x.
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