Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
55 comments Page 4 of 6.
Rajesh said:
1 decade ago
But out of four club only one queen.So the probability of getting one queen=4/52.
In my opinion answer should be [B]=2/13
P(AUB)=P(A)+P(B)=4/52+4/52=8/52=8/52=2/13
In my opinion answer should be [B]=2/13
P(AUB)=P(A)+P(B)=4/52+4/52=8/52=8/52=2/13
Kasi said:
1 decade ago
Club and heart containes 26 cards, we have to drawn a card from 26 cards so ans is 1/26.
Deepti said:
1 decade ago
There are 1 queen in club n 1 king in heart, in question we have 1 queen from club or (+) 1king from heart which implies 1 + 1 = 2, we divide it by 52 i.e. total cards and get an answer 1/26.
MOHAMMAD IMRAN said:
1 decade ago
Excellent answer by kasi.
Rajesh said:
1 decade ago
The correct answer is-
n(F)=1+1
n(T)=52c1
then,
P=n(E)/n(T)=2/52
=1/26
n(F)=1+1
n(T)=52c1
then,
P=n(E)/n(T)=2/52
=1/26
Garima gupta said:
1 decade ago
@kasi:perfect answer.
Kosakshi Pasapugazh said:
1 decade ago
Answer is 1/52.. B'coz the question is Queen OR King... Not Queen and King....
M0rfeen said:
1 decade ago
@kanan i was thinking same as you 4C1 X 4C1)/52C1
but its only right when they have asked just "queen and king" as there are 4 queen and 4 king but here they have asked "Club queen or Heart King" so there is only one Club queen and one Heart King so it's 1/52+1/52
but its only right when they have asked just "queen and king" as there are 4 queen and 4 king but here they have asked "Club queen or Heart King" so there is only one Club queen and one Heart King so it's 1/52+1/52
Subrata Acharjee said:
1 decade ago
There are 13 cards in club and 13 also in heart.
so the probability of getting a queen of club is 1/13
and the probability of getting a king of heart is 1/13
so The probability of getting a queen of club or a king of heart is (1/13 + 1/13)
= 2/13
so the probability of getting a queen of club is 1/13
and the probability of getting a king of heart is 1/13
so The probability of getting a queen of club or a king of heart is (1/13 + 1/13)
= 2/13
Raj said:
1 decade ago
Not satisfied please help
since there are 13 cards of each club and heart category and each contain single king or queen then the answer should be 1/2.
ex:(13C1+13C1)/52C1
please help if wrong
since there are 13 cards of each club and heart category and each contain single king or queen then the answer should be 1/2.
ex:(13C1+13C1)/52C1
please help if wrong
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