Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
55 comments Page 3 of 6.
Vin21 said:
8 years ago
Answer is 1/13. Because only card is drawn from 52 cards.
Bikora said:
8 years ago
@Sonam.
If we take the probability of getting a queen out of 52 cards is 4/52 and probability of getting King is 4/52. That is why the terms Club and heart are useful.
Probability of draw one card N(S)= 52C1,
Probability of queen of club n(E1)=13C1,
Probability of King of Heart n(E2) =13C1,
N(E) ={n(E1)+n(E2)}/n(S),
N(E) = (13+13)/52,
n(P) =1/26.
If we take the probability of getting a queen out of 52 cards is 4/52 and probability of getting King is 4/52. That is why the terms Club and heart are useful.
Probability of draw one card N(S)= 52C1,
Probability of queen of club n(E1)=13C1,
Probability of King of Heart n(E2) =13C1,
N(E) ={n(E1)+n(E2)}/n(S),
N(E) = (13+13)/52,
n(P) =1/26.
Kaushik raj said:
8 years ago
Here, we can use (13C1/52C1)+(13C1/52C1).
Premananda Sahoo said:
8 years ago
The probability of any two card is 2/52.
Why is the card name andcolour is specified?
Why is the card name andcolour is specified?
Sairam said:
8 years ago
Well said @Pooja.
Correct explanation, thank you very much.
Correct explanation, thank you very much.
Oman kumar said:
9 years ago
Here you said, one queen or one king. So we have to consider either king or queen right? Then the anser will be 1/52. How it's 1/26?
Ananthasubramanian said:
7 years ago
The Probability would be 1/51. The question is from the whole pack of cards & not from only Hearts & clubs, Please clarify 1/26. Thanks,
Santhosh said:
3 months ago
There is one Queen of Clubs in a standard deck of 52 playing cards. Each suit has one Queen, and the club's suit has its own Queen card.
Which means club = clever.
Which means club = clever.
Pooja said:
1 decade ago
Prob of 1 random selection n(S) = 52C1 = 52.
Queen of club = (13C1)/13 OR
King of heart = (13C1)/13.
So addition is n(E) = 2.
Finally,
p(E) = n(E)/n(S)
= 2/52 i.e 1/26.
Queen of club = (13C1)/13 OR
King of heart = (13C1)/13.
So addition is n(E) = 2.
Finally,
p(E) = n(E)/n(S)
= 2/52 i.e 1/26.
RAVULA S NARAYANA said:
1 decade ago
WE HAVE ONLY 1 QUEEN IN A CLUB AND 1 KING IN HEART SO WE HAVE TWO
EVENTS ONLY
So,
P(E) = 1/52 + 1/52
= 2/52
= 1/26.
EVENTS ONLY
So,
P(E) = 1/52 + 1/52
= 2/52
= 1/26.
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