Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
1
13
2
13
1
26
1
52
Answer: Option
Explanation:

Here, n(S) = 52.

Let E = event of getting a queen of club or a king of heart.

Then, n(E) = 2.

P(E) = n(E) = 2 = 1 .
n(S) 52 26

Discussion:
55 comments Page 1 of 6.

Kannan said:   2 decades ago
(4C1 X 4C1)/52C1

what is the error in this method? Why cant I follow this method?


I know i'm wrong, but please clarify my doubt...
Thanking you..

RAVULA S NARAYANA said:   1 decade ago
WE HAVE ONLY 1 QUEEN IN A CLUB AND 1 KING IN HEART SO WE HAVE TWO

EVENTS ONLY

So,

P(E) = 1/52 + 1/52

= 2/52

= 1/26.

Rajesh said:   1 decade ago
But out of four club only one queen.So the probability of getting one queen=4/52.
In my opinion answer should be [B]=2/13
P(AUB)=P(A)+P(B)=4/52+4/52=8/52=8/52=2/13

Kasi said:   1 decade ago
Club and heart containes 26 cards, we have to drawn a card from 26 cards so ans is 1/26.

Deepti said:   1 decade ago
There are 1 queen in club n 1 king in heart, in question we have 1 queen from club or (+) 1king from heart which implies 1 + 1 = 2, we divide it by 52 i.e. total cards and get an answer 1/26.

MOHAMMAD IMRAN said:   1 decade ago
Excellent answer by kasi.

Rajesh said:   1 decade ago
The correct answer is-
n(F)=1+1
n(T)=52c1
then,
P=n(E)/n(T)=2/52
=1/26

Garima gupta said:   1 decade ago
@kasi:perfect answer.

Kosakshi Pasapugazh said:   1 decade ago
Answer is 1/52.. B'coz the question is Queen OR King... Not Queen and King....

M0rfeen said:   1 decade ago
@kanan i was thinking same as you 4C1 X 4C1)/52C1

but its only right when they have asked just "queen and king" as there are 4 queen and 4 king but here they have asked "Club queen or Heart King" so there is only one Club queen and one Heart King so it's 1/52+1/52


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