Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
53 comments Page 1 of 6.
Rushikesh said:
2 years ago
Excellent answer, Thanks @Deepti.
(2)
Darshan said:
3 years ago
They have clearly mentioned Queen of club and king of hearts. It is common sense there is only one queen of club and king of heart.
@Abhishek
13C1 means your selecting all thirteen cards.
13C1 Gives 13,
1card cannot be selected in 13 ways.
@Abhishek
13C1 means your selecting all thirteen cards.
13C1 Gives 13,
1card cannot be selected in 13 ways.
(2)
Manish37 said:
3 years ago
You're right @Abhishek.
But we have to choose 1 out of 52 and same as king also. So the right answer is 1/26.
But we have to choose 1 out of 52 and same as king also. So the right answer is 1/26.
(1)
Abhishek Kumar said:
3 years ago
In this question, there are 13 cards in the club and we have to draw the queen of the club then 13C1 and same with the king so for that also 13C1 and because of OR operation (13C1+13C1).
So, probability will be (13C1+13C1)/52C1 = 1/2.
So, probability will be (13C1+13C1)/52C1 = 1/2.
(7)
Rishabh said:
4 years ago
@Sudhanshu I also think so.
Anubhav said:
4 years ago
In cards 1 queen of the club and 1 king of heart and sum of the digits 1+1= 2.
The porbability= 2/56 = 1/26.
The porbability= 2/56 = 1/26.
(1)
SUDHANSHU said:
4 years ago
According to me, the answer should be :: 1/2.
Because, we have total 13 card of club and 13 card of heart in which we have to select either one from them. So the overall conclusion is that:
(13C1 + 13C1) / (52C1) which will give us 1/2.
Correct me if I am wrong.
Because, we have total 13 card of club and 13 card of heart in which we have to select either one from them. So the overall conclusion is that:
(13C1 + 13C1) / (52C1) which will give us 1/2.
Correct me if I am wrong.
(2)
Suresh said:
5 years ago
In total ,there are 13 queen and 13 kings i.e .,n(S)= 26,
n(E)= 2C1 = 2 ( king or queen).
So n(P) = n(S)/n(S) = 2/26 = 1/13.
n(E)= 2C1 = 2 ( king or queen).
So n(P) = n(S)/n(S) = 2/26 = 1/13.
(1)
Amiya Acharya said:
5 years ago
In this it has been asking a queen of the club is 1C1,
A king of the heart is 1C1,
Probability = (1C1+1C1)/52C1.
A king of the heart is 1C1,
Probability = (1C1+1C1)/52C1.
(1)
GOKULAKRISHNAN.S said:
5 years ago
The answer is 1/26. The question is what the probability of queen of club & the king of heart. So the queen of the club is only one for that pack of cards. Similarly, the king of the heart is only one So, the total probability is 2.
2/52 = 1/26.
Not mention for club queen and king heart we can use normal method.
2/52 = 1/26.
Not mention for club queen and king heart we can use normal method.
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