Aptitude - Probability - Discussion

In this question, there are 13 cards in the club and we have to draw the queen of the club then 13C1 and same with the king so for that also 13C1 and because of OR operation (13C1+13C1).

So, probability will be (13C1+13C1)/52C1 = 1/2.

They have clearly mentioned Queen of club and king of hearts. It is common sense there is only one queen of club and king of heart.

@Abhishek

13C1 means your selecting all thirteen cards.
13C1 Gives 13,
1card cannot be selected in 13 ways.

In this it has been asking a queen of the club is 1C1,
A king of the heart is 1C1,
Probability = (1C1+1C1)/52C1.

In cards 1 queen of the club and 1 king of heart and sum of the digits 1+1= 2.
The porbability= 2/56 = 1/26.

Hi everyone, hope this helps you.

There are usually 4 suits of the card and each suit contains 13 cards that make (13 *4 =52).
The 4 suits are named as Club, spade, diamond and hearts. Each suit of cards contains a king and a queen.
Therefore as there are 4 suits, so there are 4 kings and 4 queens.
According to the question, Queen of the club is one of the cards from the suit of clubs and same for the king of hearts.

Therefore the probability for the queen of club or king of hearts is P (A Or B) = P (A) + P (B).

= 1/52 + 1/52 = 2/52 reducing it becomes 1/26. Hope you understand. :)

You're right @Abhishek.

But we have to choose 1 out of 52 and same as king also. So the right answer is 1/26.

In total ,there are 13 queen and 13 kings i.e .,n(S)= 26,
n(E)= 2C1 = 2 ( king or queen).

So n(P) = n(S)/n(S) = 2/26 = 1/13.

According to me, the answer should be :: 1/2.

Because, we have total 13 card of club and 13 card of heart in which we have to select either one from them. So the overall conclusion is that:

(13C1 + 13C1) / (52C1) which will give us 1/2.

Correct me if I am wrong.

Excellent answer, Thanks @Deepti.

I AM ALSO TOTALLY CONFUSED GETTING 2