Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
55 comments Page 6 of 6.
Pramod kumar jangir said:
1 decade ago
Actually, In this que. we have been asked that from the group of club and heart (13 plus 13 equal to 26) we have to extract only one card,
So that can be a queen of club (1/52) and probability of getting a king from 52 cards is 1/52,
So total probability will be sum of both the terms that is 2/52.
Or simply from 26 cards we have to take one card.
Got it.
So that can be a queen of club (1/52) and probability of getting a king from 52 cards is 1/52,
So total probability will be sum of both the terms that is 2/52.
Or simply from 26 cards we have to take one card.
Got it.
Vinod said:
1 decade ago
Its give or not and so answer will be 1c1 or 1c1/52 = 1/52.
Shailesh khare said:
1 decade ago
Both event are independent.
Therefore problem of one event is 1/52 and other is 1/52.
P(e) = 1/52+1/52 = 1/26 is right answer.
Therefore problem of one event is 1/52 and other is 1/52.
P(e) = 1/52+1/52 = 1/26 is right answer.
Arijit Biswas said:
1 decade ago
I believe OR means addition and AND means multiplication. Hence we have to add the two events i.e 1+1=2 and divide by sample space which is equal to 52 giving answer 1/26.
Shubham jain said:
10 years ago
N(E) should be 8C2? How the N(E) = 2 came?
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