Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
![]() |
n(E) | = | 2 | = | 1 | . |
n(S) | 52 | 26 |
Discussion:
55 comments Page 4 of 6.
Anil said:
9 years ago
You explained perfectly @Sonam.
Nishant sharma said:
9 years ago
@Kannan - Because we know that there is only 1 queen of club in 52 cards, here is no probability its definite so that's why we took 1+1.
Inderjeet Sahu said:
9 years ago
Most of the people said the answer is 1/26 but they don't understand or read the question carefully. In this question, the statement is clear that a one card is drawn from 52 cards, not 26, so why they, again and again, took sample space 26?
The correct answer is 2/13. Because the probability of getting queen is 4/52 i.e., 1/13 and same for the king of heart 1/13. this is because all the 4 types in the cards have 1 king, 1 Jack, 1 Queen and 1 Ace.
So the heart have its 1 king, 1 Jack, 1 Queen and 1 Ace, Diamond have its own and same for other.
The correct answer is 2/13. Because the probability of getting queen is 4/52 i.e., 1/13 and same for the king of heart 1/13. this is because all the 4 types in the cards have 1 king, 1 Jack, 1 Queen and 1 Ace.
So the heart have its 1 king, 1 Jack, 1 Queen and 1 Ace, Diamond have its own and same for other.
Aathi said:
8 years ago
What is mean a queen of club?
Unnati Gupta said:
8 years ago
Ans. is : 1/13.
n(s) = 52C1 = 52; Because we need to find the probability of getting a queen of club OR-( / ) a king of spade.
n(E) = 4C1 = 4.
n(P) = 4/52 = 1/13.
n(s) = 52C1 = 52; Because we need to find the probability of getting a queen of club OR-( / ) a king of spade.
n(E) = 4C1 = 4.
n(P) = 4/52 = 1/13.
Vin21 said:
8 years ago
Answer is 1/13. Because only card is drawn from 52 cards.
Sagar said:
8 years ago
N(E) = 1C1 + 1C1 = 1 + 1 = 2.
Bikora said:
8 years ago
@Sonam.
If we take the probability of getting a queen out of 52 cards is 4/52 and probability of getting King is 4/52. That is why the terms Club and heart are useful.
Probability of draw one card N(S)= 52C1,
Probability of queen of club n(E1)=13C1,
Probability of King of Heart n(E2) =13C1,
N(E) ={n(E1)+n(E2)}/n(S),
N(E) = (13+13)/52,
n(P) =1/26.
If we take the probability of getting a queen out of 52 cards is 4/52 and probability of getting King is 4/52. That is why the terms Club and heart are useful.
Probability of draw one card N(S)= 52C1,
Probability of queen of club n(E1)=13C1,
Probability of King of Heart n(E2) =13C1,
N(E) ={n(E1)+n(E2)}/n(S),
N(E) = (13+13)/52,
n(P) =1/26.
Premananda Sahoo said:
8 years ago
The probability of any two card is 2/52.
Why is the card name andcolour is specified?
Why is the card name andcolour is specified?
Kaushik raj said:
8 years ago
Here, we can use (13C1/52C1)+(13C1/52C1).
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers