Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
 P(E) = |
n(E) | = | 2 | = | 1 | . |
| n(S) | 52 | 26 |
Discussion:
55 comments Page 5 of 6.
Sairam said:
8 years ago
Well said @Pooja.
Correct explanation, thank you very much.
Correct explanation, thank you very much.
MR.AB said:
8 years ago
Two cards are a dream at random from a pack of 52 cards. What is the probability that they are king and queen?
Can anyone answer it?
Can anyone answer it?
Ananthasubramanian said:
7 years ago
The Probability would be 1/51. The question is from the whole pack of cards & not from only Hearts & clubs, Please clarify 1/26. Thanks,
GOKULAKRISHNAN.S said:
7 years ago
The answer is 1/26. The question is what the probability of queen of club & the king of heart. So the queen of the club is only one for that pack of cards. Similarly, the king of the heart is only one So, the total probability is 2.
2/52 = 1/26.
Not mention for club queen and king heart we can use normal method.
2/52 = 1/26.
Not mention for club queen and king heart we can use normal method.
(1)
Amiya Acharya said:
7 years ago
In this it has been asking a queen of the club is 1C1,
A king of the heart is 1C1,
Probability = (1C1+1C1)/52C1.
A king of the heart is 1C1,
Probability = (1C1+1C1)/52C1.
(6)
Suresh said:
7 years ago
In total ,there are 13 queen and 13 kings i.e .,n(S)= 26,
n(E)= 2C1 = 2 ( king or queen).
So n(P) = n(S)/n(S) = 2/26 = 1/13.
n(E)= 2C1 = 2 ( king or queen).
So n(P) = n(S)/n(S) = 2/26 = 1/13.
(2)
SUDHANSHU said:
6 years ago
According to me, the answer should be :: 1/2.
Because, we have total 13 card of club and 13 card of heart in which we have to select either one from them. So the overall conclusion is that:
(13C1 + 13C1) / (52C1) which will give us 1/2.
Correct me if I am wrong.
Because, we have total 13 card of club and 13 card of heart in which we have to select either one from them. So the overall conclusion is that:
(13C1 + 13C1) / (52C1) which will give us 1/2.
Correct me if I am wrong.
(2)
Anubhav said:
6 years ago
In cards 1 queen of the club and 1 king of heart and sum of the digits 1+1= 2.
The porbability= 2/56 = 1/26.
The porbability= 2/56 = 1/26.
(6)
Rishabh said:
6 years ago
@Sudhanshu I also think so.
(1)
Abhishek Kumar said:
5 years ago
In this question, there are 13 cards in the club and we have to draw the queen of the club then 13C1 and same with the king so for that also 13C1 and because of OR operation (13C1+13C1).
So, probability will be (13C1+13C1)/52C1 = 1/2.
So, probability will be (13C1+13C1)/52C1 = 1/2.
(16)
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