Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 11)
11.
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
![]() |
n(E) | = | 2 | = | 1 | . |
n(S) | 52 | 26 |
Discussion:
55 comments Page 3 of 6.
Pavan Mitra said:
1 decade ago
By or we mean either a king of heart or a queen of clubs, so p(king of heart)=1/52=p(queen of clubs) and n(e)=2, So p=2/52=1/26.
Sonam said:
1 decade ago
Guys, please try my solution.
The formula for probability is :
P(E) = n(E)/n(S).
Here, P(E) = probability of an event.
n(E) = total no.of drawn cards.
n(S) = total no.of cards.
Here, n(E) = 1 = total no.of drawn cards.
( because only one card is drawn from a pack of
52 cards.)
n(S) = 52 = total no.of cards.
(because total no.of cards we have 52.).
Firstly, we will apply this formula for first part of this question, i.e; getting a queen out of 52 cards. (please forget club or heart. Because it is given for confusing us. There is no use of it.).
So, Apply formula :
P(E) = n(E)/n(S).
= 1/52.
Now, we will apply this formula in the second part of the question, i.e; getting a king out of 52 cards.
P(E)= n(E)/n(S).
= 1/52.
Now, in the question, the case is given that : getting a queen or a king. Here 'or' means '+' .
Now we will apply '+' sign between these two cases.
The probability of getting a king or a queen is :
= 1/52 + 1/52.
= 2 * 1/52.
= 2/52.
= 1/26.
The formula for probability is :
P(E) = n(E)/n(S).
Here, P(E) = probability of an event.
n(E) = total no.of drawn cards.
n(S) = total no.of cards.
Here, n(E) = 1 = total no.of drawn cards.
( because only one card is drawn from a pack of
52 cards.)
n(S) = 52 = total no.of cards.
(because total no.of cards we have 52.).
Firstly, we will apply this formula for first part of this question, i.e; getting a queen out of 52 cards. (please forget club or heart. Because it is given for confusing us. There is no use of it.).
So, Apply formula :
P(E) = n(E)/n(S).
= 1/52.
Now, we will apply this formula in the second part of the question, i.e; getting a king out of 52 cards.
P(E)= n(E)/n(S).
= 1/52.
Now, in the question, the case is given that : getting a queen or a king. Here 'or' means '+' .
Now we will apply '+' sign between these two cases.
The probability of getting a king or a queen is :
= 1/52 + 1/52.
= 2 * 1/52.
= 2/52.
= 1/26.
Pramod kumar jangir said:
1 decade ago
Actually, In this que. we have been asked that from the group of club and heart (13 plus 13 equal to 26) we have to extract only one card,
So that can be a queen of club (1/52) and probability of getting a king from 52 cards is 1/52,
So total probability will be sum of both the terms that is 2/52.
Or simply from 26 cards we have to take one card.
Got it.
So that can be a queen of club (1/52) and probability of getting a king from 52 cards is 1/52,
So total probability will be sum of both the terms that is 2/52.
Or simply from 26 cards we have to take one card.
Got it.
Vinod said:
1 decade ago
Its give or not and so answer will be 1c1 or 1c1/52 = 1/52.
Shailesh khare said:
1 decade ago
Both event are independent.
Therefore problem of one event is 1/52 and other is 1/52.
P(e) = 1/52+1/52 = 1/26 is right answer.
Therefore problem of one event is 1/52 and other is 1/52.
P(e) = 1/52+1/52 = 1/26 is right answer.
Arijit Biswas said:
1 decade ago
I believe OR means addition and AND means multiplication. Hence we have to add the two events i.e 1+1=2 and divide by sample space which is equal to 52 giving answer 1/26.
Shubham jain said:
10 years ago
N(E) should be 8C2? How the N(E) = 2 came?
Oman kumar said:
9 years ago
Here you said, one queen or one king. So we have to consider either king or queen right? Then the anser will be 1/52. How it's 1/26?
Saurav said:
9 years ago
Hi everyone, hope this helps you.
There are usually 4 suits of the card and each suit contains 13 cards that make (13 *4 =52).
The 4 suits are named as Club, spade, diamond and hearts. Each suit of cards contains a king and a queen.
Therefore as there are 4 suits, so there are 4 kings and 4 queens.
According to the question, Queen of the club is one of the cards from the suit of clubs and same for the king of hearts.
Therefore the probability for the queen of club or king of hearts is P (A Or B) = P (A) + P (B).
= 1/52 + 1/52 = 2/52 reducing it becomes 1/26. Hope you understand. :)
There are usually 4 suits of the card and each suit contains 13 cards that make (13 *4 =52).
The 4 suits are named as Club, spade, diamond and hearts. Each suit of cards contains a king and a queen.
Therefore as there are 4 suits, so there are 4 kings and 4 queens.
According to the question, Queen of the club is one of the cards from the suit of clubs and same for the king of hearts.
Therefore the probability for the queen of club or king of hearts is P (A Or B) = P (A) + P (B).
= 1/52 + 1/52 = 2/52 reducing it becomes 1/26. Hope you understand. :)
(3)
Vani said:
9 years ago
For this question, I got the answer as 2/13. But how it is 1/26? I don't no please tell me.
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