Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 5 of 18.
Person said:
1 decade ago
Good. @hiren.
(2)
Divyanshu said:
1 decade ago
Hw we can calcuate, total marks ?
(2)
Uttam said:
1 decade ago
First find total marks
difference between percentage=56%-44%=9%
In the question given difference between marks as 12
so, if mark is percentage
9 12%
? 100%
so by cross multiplying total marks=(9*100)/12=75.
now student 1s marks=56% of 75 i.e
(56/100)*75=42.
student 2s marks=44% of 75 i.e
(44/100)*75=33.
difference between percentage=56%-44%=9%
In the question given difference between marks as 12
so, if mark is percentage
9 12%
? 100%
so by cross multiplying total marks=(9*100)/12=75.
now student 1s marks=56% of 75 i.e
(56/100)*75=42.
student 2s marks=44% of 75 i.e
(44/100)*75=33.
(2)
Radhika said:
1 decade ago
56-44/100=9
12/100=9
=75
now
56/100*75=42
44/100*75=33
:)
12/100=9
=75
now
56/100*75=42
44/100*75=33
:)
(2)
Ganesh said:
1 decade ago
very 1 stape is just to calculate total marks in each option,
suppose, I'm choosing 39 30 then total marks are 69 which is 100% if u calculate 56% of 69 i.e 56*69/100 you get 38.64 which is not in option. so leave it there.
if you're taking 42 33 then total marks are 75 which is 100% and 56% of 75 is 42 hence option C is correct.
though it is lengthy procedure, we can choose the option for calculation by little thinking before solving it.
suppose, I'm choosing 39 30 then total marks are 69 which is 100% if u calculate 56% of 69 i.e 56*69/100 you get 38.64 which is not in option. so leave it there.
if you're taking 42 33 then total marks are 75 which is 100% and 56% of 75 is 42 hence option C is correct.
though it is lengthy procedure, we can choose the option for calculation by little thinking before solving it.
(2)
Aparna said:
2 decades ago
Suppose 1 students score is 'x',then others will be 'x+9'
Now the next information is given about the student whose score is 'x+9'
Whenever in the question 'and'/'is' given put '=' sign
56% means 56/100 ,of means put multiplication sign
and sum of the marks means(x+x+9)
Now just solve the equation.
Now the next information is given about the student whose score is 'x+9'
Whenever in the question 'and'/'is' given put '=' sign
56% means 56/100 ,of means put multiplication sign
and sum of the marks means(x+x+9)
Now just solve the equation.
(1)
Vel said:
1 decade ago
Ok why equal sign assigned b/w x+9 and 56/100 (x+9+x) ?
(1)
Prasad said:
1 decade ago
@aparna..Hi..could it possible to put in details.please
(1)
Krishna said:
1 decade ago
@uttam
How it can be 56%-44%=9%?
Can you explain it?
How it can be 56%-44%=9%?
Can you explain it?
(1)
Neelu said:
1 decade ago
Let mark of person A = x.
Mark of person B = x+9.
Total marks secured by both A & B = x+(x+9).
Since %mark of person B = 56/100(x+(x+9)).
Therefore x+9 = 56/100(x+(x+9)).
x+9 = 14/25(2x+9).
25(x+9) = 14(2x+9).
25x+225 = 28x + 126.
28x-25x = 225 - 126.
3x = 99.
x = 99/3.
x = 33.
Hence mark of person A = 33.
Mark of person B = 33+9 = 42.
Mark of person B = x+9.
Total marks secured by both A & B = x+(x+9).
Since %mark of person B = 56/100(x+(x+9)).
Therefore x+9 = 56/100(x+(x+9)).
x+9 = 14/25(2x+9).
25(x+9) = 14(2x+9).
25x+225 = 28x + 126.
28x-25x = 225 - 126.
3x = 99.
x = 99/3.
x = 33.
Hence mark of person A = 33.
Mark of person B = 33+9 = 42.
(1)
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