Aptitude - Percentage - Discussion

56-44/100=9
12/100=9
=75
now
56/100*75=42
44/100*75=33
:)

very 1 stape is just to calculate total marks in each option,
suppose, I'm choosing 39 30 then total marks are 69 which is 100% if u calculate 56% of 69 i.e 56*69/100 you get 38.64 which is not in option. so leave it there.

if you're taking 42 33 then total marks are 75 which is 100% and 56% of 75 is 42 hence option C is correct.

though it is lengthy procedure, we can choose the option for calculation by little thinking before solving it.

Suppose 1 students score is 'x',then others will be 'x+9'

Now the next information is given about the student whose score is 'x+9'

Whenever in the question 'and'/'is' given put '=' sign
56% means 56/100 ,of means put multiplication sign
and sum of the marks means(x+x+9)

Now just solve the equation.

Ok why equal sign assigned b/w x+9 and 56/100 (x+9+x) ?

@aparna..Hi..could it possible to put in details.please

@uttam

How it can be 56%-44%=9%?

Can you explain it?

Let mark of person A = x.
Mark of person B = x+9.

Total marks secured by both A & B = x+(x+9).
Since %mark of person B = 56/100(x+(x+9)).
Therefore x+9 = 56/100(x+(x+9)).

x+9 = 14/25(2x+9).
25(x+9) = 14(2x+9).
25x+225 = 28x + 126.
28x-25x = 225 - 126.

3x = 99.
x = 99/3.
x = 33.

Hence mark of person A = 33.
Mark of person B = 33+9 = 42.

Its very simple.

What is the % difference 12% mark difference 9 if 12% = 9; 56%=?

56*9/12 = 42 which is highest mark.

So 42-9 = 33.

Answer is 42, 33.

Dear @Chandan it is very simple,

Two students total mark in percentage is 56% that mention in the question.

If we discuss this line the result is x+y = 56%.

But the question says one of them secured 9 marks than other.

So we assume one student is (x+9) and other is x.

Here x+9 means x+9 is secured 9 marks extra than x.

Now if we try to find out the value of x from x+9. If we find out the x output then we must find out both students mark.

x+9 = 56(x+9+x)/100 [here we write 56(x+9+x) means both students percentage is 56%].

x+9 = 14(x+9+x)/25.
25(x+9) = 14(2x+9).

3x = 99 [25x+225 = 28x+126 => 28x-25x = 225-126 =>3x = 99].

x = 33[x = 99/3 => 33].

Now the original output is:

Two students are: x, (x+9).

1st student's mark is: x = 33.

2nd student is secured 9 marks than 1st student => (x+9) = 33+9 = 42.

Output option is C: 42, 33.

I am confused it says the sum of their marks. Then it should be like this.

x + x + 9 = 56/100.

Can anyone explain this?