Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 6 of 18.
Suren said:
1 decade ago
Its very simple.
What is the % difference 12% mark difference 9 if 12% = 9; 56%=?
56*9/12 = 42 which is highest mark.
So 42-9 = 33.
Answer is 42, 33.
What is the % difference 12% mark difference 9 if 12% = 9; 56%=?
56*9/12 = 42 which is highest mark.
So 42-9 = 33.
Answer is 42, 33.
(1)
Tukuna Behera said:
1 decade ago
Dear @Chandan it is very simple,
Two students total mark in percentage is 56% that mention in the question.
If we discuss this line the result is x+y = 56%.
But the question says one of them secured 9 marks than other.
So we assume one student is (x+9) and other is x.
Here x+9 means x+9 is secured 9 marks extra than x.
Now if we try to find out the value of x from x+9. If we find out the x output then we must find out both students mark.
x+9 = 56(x+9+x)/100 [here we write 56(x+9+x) means both students percentage is 56%].
x+9 = 14(x+9+x)/25.
25(x+9) = 14(2x+9).
3x = 99 [25x+225 = 28x+126 => 28x-25x = 225-126 =>3x = 99].
x = 33[x = 99/3 => 33].
Now the original output is:
Two students are: x, (x+9).
1st student's mark is: x = 33.
2nd student is secured 9 marks than 1st student => (x+9) = 33+9 = 42.
Output option is C: 42, 33.
Two students total mark in percentage is 56% that mention in the question.
If we discuss this line the result is x+y = 56%.
But the question says one of them secured 9 marks than other.
So we assume one student is (x+9) and other is x.
Here x+9 means x+9 is secured 9 marks extra than x.
Now if we try to find out the value of x from x+9. If we find out the x output then we must find out both students mark.
x+9 = 56(x+9+x)/100 [here we write 56(x+9+x) means both students percentage is 56%].
x+9 = 14(x+9+x)/25.
25(x+9) = 14(2x+9).
3x = 99 [25x+225 = 28x+126 => 28x-25x = 225-126 =>3x = 99].
x = 33[x = 99/3 => 33].
Now the original output is:
Two students are: x, (x+9).
1st student's mark is: x = 33.
2nd student is secured 9 marks than 1st student => (x+9) = 33+9 = 42.
Output option is C: 42, 33.
(1)
Bgnr said:
9 years ago
I am confused it says the sum of their marks. Then it should be like this.
x + x + 9 = 56/100.
Can anyone explain this?
x + x + 9 = 56/100.
Can anyone explain this?
(1)
AlikaRai said:
9 years ago
I need help for this question. Kindly help me.
If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.
If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.
(1)
Kalyan said:
8 years ago
Let both of them be A and B.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).
Where A= 9+x.
By equating we can get x value 33.
A = 33+9 = 42.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).
Where A= 9+x.
By equating we can get x value 33.
A = 33+9 = 42.
(1)
Md Attaullah said:
6 years ago
As per my method, the Solution is;
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.
(1)
Deepika said:
6 years ago
@Anthea. You do by simply dividing 56/100 by least divisible 2 then you got answer 14/25. Hope it's clear !
(1)
Harsha said:
5 years ago
Why we make x+x+9 their? I am not getting that, Anyone explain me.
(1)
Nisma said:
5 years ago
2 numbers are (x) and (x+9).
Now,
(x+9) =56% of (x+x+9),
=(2x+9)56%.
Now open brackets
x+9 = 112x/100 + 504/100,
9 - (504/100 ) = (112x-100x)/100,
(900-504)/100= 12x /100,
396/100 = 12x/100.
>> 396 = 12x.
396/12 = x
33=x,
So 2 digits are:
x = 33,
x+9 = 42.
Now,
(x+9) =56% of (x+x+9),
=(2x+9)56%.
Now open brackets
x+9 = 112x/100 + 504/100,
9 - (504/100 ) = (112x-100x)/100,
(900-504)/100= 12x /100,
396/100 = 12x/100.
>> 396 = 12x.
396/12 = x
33=x,
So 2 digits are:
x = 33,
x+9 = 42.
(1)
Naina said:
4 years ago
Thanks @Diksha.
(1)
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