Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 6 of 17.
AlikaRai said:
8 years ago
I need help for this question. Kindly help me.
If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.
If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.
(1)
Kalyan said:
7 years ago
Let both of them be A and B.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).
Where A= 9+x.
By equating we can get x value 33.
A = 33+9 = 42.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).
Where A= 9+x.
By equating we can get x value 33.
A = 33+9 = 42.
(1)
Md Attaullah said:
6 years ago
As per my method, the Solution is;
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.
(1)
Deepika said:
6 years ago
@Anthea. You do by simply dividing 56/100 by least divisible 2 then you got answer 14/25. Hope it's clear !
(1)
Harsha said:
5 years ago
Why we make x+x+9 their? I am not getting that, Anyone explain me.
(1)
Nisma said:
5 years ago
2 numbers are (x) and (x+9).
Now,
(x+9) =56% of (x+x+9),
=(2x+9)56%.
Now open brackets
x+9 = 112x/100 + 504/100,
9 - (504/100 ) = (112x-100x)/100,
(900-504)/100= 12x /100,
396/100 = 12x/100.
>> 396 = 12x.
396/12 = x
33=x,
So 2 digits are:
x = 33,
x+9 = 42.
Now,
(x+9) =56% of (x+x+9),
=(2x+9)56%.
Now open brackets
x+9 = 112x/100 + 504/100,
9 - (504/100 ) = (112x-100x)/100,
(900-504)/100= 12x /100,
396/100 = 12x/100.
>> 396 = 12x.
396/12 = x
33=x,
So 2 digits are:
x = 33,
x+9 = 42.
(1)
Naina said:
4 years ago
Thanks @Diksha.
(1)
Archana said:
1 decade ago
How do you come on this step
x + 9 = 56/100 (x + 9 + x)
25(x + 9) = 14(2x + 9)
Please explain in simple way.
x + 9 = 56/100 (x + 9 + x)
25(x + 9) = 14(2x + 9)
Please explain in simple way.
Ashok said:
1 decade ago
@Archana:
Divide 56/100 by 4 and you'll Get 14/25
bring the 25 to L.H.S
and you will get
25(x+9)=14(x+9+x)
now add two x's in R.H.S
25(x+9)=14(2x+9)
Divide 56/100 by 4 and you'll Get 14/25
bring the 25 to L.H.S
and you will get
25(x+9)=14(x+9+x)
now add two x's in R.H.S
25(x+9)=14(2x+9)
Suraj said:
1 decade ago
25X+225=28X+126
28X=25X+225-126
28X=25X+99
28X-25X=99
3X=99
X=99/3
X=33
Ans:x=33; x+9=33+9=42.
28X=25X+225-126
28X=25X+99
28X-25X=99
3X=99
X=99/3
X=33
Ans:x=33; x+9=33+9=42.
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