Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 18 of 18.
Gaurav said:
5 years ago
@Geetha.
It comes 25/14 when you divide 56/100.
It comes 25/14 when you divide 56/100.
Jeeva said:
5 years ago
@Vel.
Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.
Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.
Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.
Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.
Balaganesh said:
5 years ago
@Pawan.
From the QN, Sum of their mark % is 56%.
From the QN, Sum of their mark % is 56%.
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