# Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)

2.

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

Answer: Option

Explanation:

Let their marks be (*x* + 9) and *x*.

Then, x + 9 = |
56 | (x + 9 + x) |

100 |

25(*x* + 9) = 14(2*x* + 9)

3*x* = 99

*x* = 33

So, their marks are 42 and 33.

Discussion:

153 comments Page 1 of 16.
Moli said:
2 weeks ago

Total =100

F= 56%

S = ?.

So,

X = 100 - 56 = 44.

44 - 9 = 33.

F= 56%

S = ?.

So,

X = 100 - 56 = 44.

44 - 9 = 33.

(15)

AVINASH KUMAR said:
8 months ago

A and B is there;

A + B = 100.

A = 56,B = 44,A - B = 12.

12%U = 9

12/100U = 9

3/25U = 9

3U = 9

1U = 3

A = 56% = 56/100,14/25U

A = 14U = 14 * 3 = 42

B = 11U = 11 * 3 = 33.

A + B = 100.

A = 56,B = 44,A - B = 12.

12%U = 9

12/100U = 9

3/25U = 9

3U = 9

1U = 3

A = 56% = 56/100,14/25U

A = 14U = 14 * 3 = 42

B = 11U = 11 * 3 = 33.

(33)

Shakthi said:
8 months ago

Let one student obtain x marks.

So, another obtained x+9 marks.

According to the question;

X+9 = 56/100'- (2x+9).

By cross multiplying.

3x = 99.

x = 33.

So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.

So, another obtained x+9 marks.

According to the question;

X+9 = 56/100'- (2x+9).

By cross multiplying.

3x = 99.

x = 33.

So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.

(27)

Suresh said:
10 months ago

Total mark% = 56.

Then the remaining percentage= 100 - 56 = 44%.

Difference percentage = 56-44 = 12%.

Then the difference mark= 9.

So, 12 percentage = 9 then what percent = 56% = 42.

42-9 = 33.

Then the remaining percentage= 100 - 56 = 44%.

Difference percentage = 56-44 = 12%.

Then the difference mark= 9.

So, 12 percentage = 9 then what percent = 56% = 42.

42-9 = 33.

(249)

Ritesh Rawal said:
1 year ago

Your explanation is simple & clear. Thank you very much @Neelu.

(19)

Arjun said:
1 year ago

Why we Equalize 56/100 (2x+9) into x+9? can anyone please explain this?

(14)

Chernet said:
2 years ago

Thanks all for giving an excellent explanation.

(7)

Dr.Mahaveer said:
2 years ago

@All.

Hello.

Simply, the solution is;

A = x+9,

B = x,

x+9 = 56%(x+x+9),

x+9 = 56/100(2x+9),

x = 33,

A = 33 + 9 = 42.

B = 33.

Hello.

Simply, the solution is;

A = x+9,

B = x,

x+9 = 56%(x+x+9),

x+9 = 56/100(2x+9),

x = 33,

A = 33 + 9 = 42.

B = 33.

(33)

Aarti said:
2 years ago

Difference of the both students marks:

56% - 44% = 12%.

Difference is = 9

12% = 9

1% = 9/12

100% = 9*100/12 = 75.

Total marks = 75.

56% of total marks = 75*56/100 = 42.

42-9 = 33.

56% - 44% = 12%.

Difference is = 9

12% = 9

1% = 9/12

100% = 9*100/12 = 75.

Total marks = 75.

56% of total marks = 75*56/100 = 42.

42-9 = 33.

(90)

Rohit said:
2 years ago

Thank you for explaining @Rahul.

(3)

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