Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
161 comments Page 1 of 17.

Komal said:   1 month ago
Let 1st student (A) marks = x.
Therefore,
2nd student (B) marks = x+9.
Now , x+9 = 56% of {(x+9)+(x)}.
=> x+9= 56/100 (x+9+x),
=> x+9 = 0.56(x+9+x),
=> x+9 = 0.56x + 0.56x + 5.04,
=> x+9 = 1.12x + 5.04,
=> x-1.12x = 9 - 5.04,
=> 0.12x = 3.96.
=> x = 3.96/0.12.
=> Marks of A = [x = 33].
Therefore, Marks of B = x+9.
=> 33+9 = 42.
(3)

Anke Lakshmi said:   3 months ago
Let the marks obtained by the students be a and b:

Let a = b + 9 -------->1
a = (56/100) * (a+b) ---------> 2.

From equation 1, equation 2 can be written as;

b + 9 = (0.56) * (b + 9 + b),
b + 9 = (0.56)(2b + 9).
b + 9 = 1.12b + 5.04
9 - 5.04 = 1.12b - b.
3.96 = 0.12b,
b = 3.96/0.12,
b = 33.

Then, a=b+9
a=33+9
a=42

Therefore, marks scored by a and b are 42 and 33.
(5)

Nagajothi said:   4 months ago
Obtained mark % = 56.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.
(115)

Parvathi said:   5 months ago
Let total marks be =100.
F =56%.

Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
(129)

Shahid Afridi said:   5 months ago
@All

Here, some people doing the wrong calculation 44-9=35 not 33. Please correct it.
(62)

Jayendra Malviya said:   5 months ago
Obtained mark% = 56 and Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.
(41)

Santhiya said:   7 months ago
Total = 100.
F = 56%,

Therefore;
X = 100 - 56 = 44.
44 - 9 = X = 33.
(76)

Naveen Thonpunoori said:   7 months ago
Let's say X, and Y are students.

We can say Y got 44% of the total marks since X got 56%.
Percentage difference b/w X, Y is 56%- 44% = 12%.
X got 9 marks more than Y, So 9 marks are equal to 12%.
So, 1% of marks equal to, 9/12 = 0.75,
X marks are, 0.75 * 56 = 42.
Y marks are, 0.75 * 44 = 33.
(52)

Moli said:   8 months ago
Total =100
F= 56%
S = ?.

So,
X = 100 - 56 = 44.
44 - 9 = 33.
(87)

AVINASH KUMAR said:   1 year ago
A and B is there;

A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
(37)


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