Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 1 of 18.
Srabani guntha said:
2 weeks ago
Let the student are;
a,b and their marks are x and x+9
As the question is given,
from the question we get.
x+x+9(56/100) = x+9.
Because the question is said 56 per cent of the sum of their mark;
So 2x+9 (56/100) = x+9,
(112x +504)/100 = x + 9,
112x +504 = 100x + 900,
112x-100x = 900 - 504.
12x = 396.
x = 33.
and x + 9 = 33 + 9,
= 42.
So the mark are 33 and 42.
a,b and their marks are x and x+9
As the question is given,
from the question we get.
x+x+9(56/100) = x+9.
Because the question is said 56 per cent of the sum of their mark;
So 2x+9 (56/100) = x+9,
(112x +504)/100 = x + 9,
112x +504 = 100x + 900,
112x-100x = 900 - 504.
12x = 396.
x = 33.
and x + 9 = 33 + 9,
= 42.
So the mark are 33 and 42.
(2)
Preetika said:
4 weeks ago
How 25 has come? Please explain to me.
(2)
Krishnaa Kumari said:
2 months ago
Total marks = 100%.
X = 56%.
Y = 100-56.
= 44%.
Now the difference marks between X and Y.
= (56-44)%,
= 12%.
Now,
12% = 9,
1% = 9÷12,
56%= 9÷12 × 56,
= 42.
Next;
Y = 44%.
12% = 9.
1% = 9÷12,
44%= 9÷12 × 44,
= 33.
X = 56%.
Y = 100-56.
= 44%.
Now the difference marks between X and Y.
= (56-44)%,
= 12%.
Now,
12% = 9,
1% = 9÷12,
56%= 9÷12 × 56,
= 42.
Next;
Y = 44%.
12% = 9.
1% = 9÷12,
44%= 9÷12 × 44,
= 33.
(40)
Boopathi said:
4 months ago
25(x+9) = 14(2x+9),
25x + 234 = 28x + 126,
25x - 28x = 126 - 234,
3x = 108,
x = 108/3,
x = 33,
y = 33 + 9 = 42.
25x + 234 = 28x + 126,
25x - 28x = 126 - 234,
3x = 108,
x = 108/3,
x = 33,
y = 33 + 9 = 42.
(12)
Shahira said:
4 months ago
2 students appeared for the exam.
1 -> 56% and 9 mark more than others,
1 -> x+9.
2 -> x.
x+9 = 56% of (x+9 +x),
x+9 = 56/100 (2x+9),
100(x+9) = 56 (2x + 9),
100x + 900 = 112x + 504,
100x - 112x + 900 - 504 = 0 .
-12x + 396 = 0,
12x = 396.
x = 396/12.
x = 33.
1 -> x+9 = 33+9 = 42.
2-> 33.
So, the answer is 42 and 33.
1 -> 56% and 9 mark more than others,
1 -> x+9.
2 -> x.
x+9 = 56% of (x+9 +x),
x+9 = 56/100 (2x+9),
100(x+9) = 56 (2x + 9),
100x + 900 = 112x + 504,
100x - 112x + 900 - 504 = 0 .
-12x + 396 = 0,
12x = 396.
x = 396/12.
x = 33.
1 -> x+9 = 33+9 = 42.
2-> 33.
So, the answer is 42 and 33.
(37)
Jeni said:
6 months ago
Let the marks of the first student be x.
Then, the other student got x + 9 marks.
Total marks = x + (x + 9) = 2x + 9,
Given: x + 9 = 56% of (2x + 9),
=> x + 9 = 0.56(2x + 9),
=> x + 9 = 1.12x + 5.04,
=> -0.12x = -3.96,
=> x = 33,
So, the other student got 33 + 9 = 42.
Answer: 33 and 42 marks.
Then, the other student got x + 9 marks.
Total marks = x + (x + 9) = 2x + 9,
Given: x + 9 = 56% of (2x + 9),
=> x + 9 = 0.56(2x + 9),
=> x + 9 = 1.12x + 5.04,
=> -0.12x = -3.96,
=> x = 33,
So, the other student got 33 + 9 = 42.
Answer: 33 and 42 marks.
(23)
Sakshi Shinde said:
6 months ago
@All.
Let the marks of the first student be x.
Then, the other student got x + 9 marks.
Total marks = x + (x + 9) = 2x + 9,
Given: x + 9 = 56% of (2x + 9),
=> x + 9 = 0.56(2x + 9),
=> x + 9 = 1.12x + 5.04,
=> -0.12x = -3.96,
=> x = 33,
So, the other student got 33 + 9 = 42.
Answer: 33 and 42 marks.
Let the marks of the first student be x.
Then, the other student got x + 9 marks.
Total marks = x + (x + 9) = 2x + 9,
Given: x + 9 = 56% of (2x + 9),
=> x + 9 = 0.56(2x + 9),
=> x + 9 = 1.12x + 5.04,
=> -0.12x = -3.96,
=> x = 33,
So, the other student got 33 + 9 = 42.
Answer: 33 and 42 marks.
(26)
Chahat Mishra tcet said:
9 months ago
VERY EASY:
Let total marks be = 100.
F =56%.
Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
Let total marks be = 100.
F =56%.
Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.
(545)
Vijay Kumar said:
9 months ago
Total marks = 100%
Obtained marks"×" = 56%
"Y" = 44%.
Here difference is = 12%(it means 9)
So each 1% = 0.75.
10% = 7.5 {100% = 75; 50% = 37.5; 6% = 4.50}
So 56%= 42{ 37.5 + 4.5}.
44% = 33{37.5 - 4.5}.
Obtained marks"×" = 56%
"Y" = 44%.
Here difference is = 12%(it means 9)
So each 1% = 0.75.
10% = 7.5 {100% = 75; 50% = 37.5; 6% = 4.50}
So 56%= 42{ 37.5 + 4.5}.
44% = 33{37.5 - 4.5}.
(32)
Upasana said:
9 months ago
@All.
I have a solution.
56% = 56\100 = 14\25.
Let's take the total mark = 25.
The higher scorer's mark = 14.
The lower scorer's mark =25 - 14 = 11
The difference given in the question is 9 so,
14parts - 11parts = 9,
value of 3 parts = 9,
so the value of 1 part = 9\3= 3.
Now we have to calculate higher scorer's marks = 14 * 3 = 42.
Then we have to calculate the lower scorer's marks = 11 * 3 = 33.
I have a solution.
56% = 56\100 = 14\25.
Let's take the total mark = 25.
The higher scorer's mark = 14.
The lower scorer's mark =25 - 14 = 11
The difference given in the question is 9 so,
14parts - 11parts = 9,
value of 3 parts = 9,
so the value of 1 part = 9\3= 3.
Now we have to calculate higher scorer's marks = 14 * 3 = 42.
Then we have to calculate the lower scorer's marks = 11 * 3 = 33.
(23)
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