Aptitude - Percentage - Discussion

Discussion :: Percentage - General Questions (Q.No.2)

2. 

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

[A]. 39, 30
[B]. 41, 32
[C]. 42, 33
[D]. 43, 34

Answer: Option C

Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.


Ramya said: (Dec 29, 2010)  
Please explain in simple way.

Aparna said: (Dec 29, 2010)  
Suppose 1 students score is 'x',then others will be 'x+9'

Now the next information is given about the student whose score is 'x+9'

Whenever in the question 'and'/'is' given put '=' sign
56% means 56/100 ,of means put multiplication sign
and sum of the marks means(x+x+9)

Now just solve the equation.

Vel said: (Feb 17, 2011)  
Ok why equal sign assigned b/w x+9 and 56/100 (x+9+x) ?

Hiren Savalia said: (May 7, 2011)  
Go by option u will get answer easily ...

Let me choose 42 & 33

As all answers have difference of 9 so next step is to check 56 % condition for this answer ....

Now 56 % of sum of marks means 75 is 100 % then 42 is how much ?
calculate & u will get 56 % so u will come to know that the answer that u have chosen is d ri8 1 ... enjy :)

Person said: (Jul 2, 2011)  
Good. @hiren.

Divyanshu said: (Jul 6, 2011)  
Hw we can calcuate, total marks ?

Prasad said: (Sep 5, 2011)  
@aparna..Hi..could it possible to put in details.please

Uttam said: (Sep 18, 2011)  
First find total marks

difference between percentage=56%-44%=9%

In the question given difference between marks as 12

so, if mark is percentage

9 12%

? 100%

so by cross multiplying total marks=(9*100)/12=75.

now student 1s marks=56% of 75 i.e

(56/100)*75=42.

student 2s marks=44% of 75 i.e

(44/100)*75=33.

Krishna said: (Nov 1, 2011)  
@uttam

How it can be 56%-44%=9%?

Can you explain it?

Radhika said: (Nov 5, 2011)  
56-44/100=9
12/100=9
=75
now
56/100*75=42
44/100*75=33
:)

Archana said: (Jan 20, 2012)  
How do you come on this step

x + 9 = 56/100 (x + 9 + x)
25(x + 9) = 14(2x + 9)
Please explain in simple way.

Ashok said: (Jan 20, 2012)  
@Archana:

Divide 56/100 by 4 and you'll Get 14/25
bring the 25 to L.H.S
and you will get
25(x+9)=14(x+9+x)
now add two x's in R.H.S
25(x+9)=14(2x+9)

Suraj said: (Feb 19, 2012)  
25X+225=28X+126
28X=25X+225-126
28X=25X+99
28X-25X=99
3X=99
X=99/3
X=33
Ans:x=33; x+9=33+9=42.

Mohit said: (Mar 5, 2012)  
How did you that 25, 225, 28, 126 ?

Maryam said: (Jun 6, 2012)  
y u write (x+9+x)on the other side of equalto

Vino said: (Jun 16, 2012)  
No confusion. Listen.
Assume total marks will be 100,
One student=x+9.

Another=x.
So,
For 100 he scored 56, so what marks for them so (x+9+x).
56/100* (x+9+x).

Now x+9 is student 1: So equate,

x+9 = 56/100* (x+9+x).

Anthea said: (Aug 21, 2012)  
@Ashok

Y did u divide 56/100 by 4?

Anthea said: (Aug 21, 2012)  
@Ashok

Y did u divide 56/100 by 4?

Hemant Singh said: (Aug 22, 2012)  
By question let first scoted x marks

then 2nd x+9
sum of ther marks {x+x+9}
not by ques the student who ha s scored x+9 marks = su m of marks of both students ie x+9=2x+9 of 56%
solve it now

Viral said: (Aug 24, 2012)  
@Radhika
How can u write this eq.
56-44/100=9
means why u put 9 to the R.H.S?

Bm Naidu said: (Aug 28, 2012)  
Why we equqte x+9&(56/100(x+9+x)?

Can u please explain in simple way.

Sarwat said: (Sep 7, 2012)  
30 percent of a number is 180. What is 15 percent of 3 times of the same number?

Please help me in this question.

Suhas said: (Sep 15, 2012)  
Instead of calculating using variables, use options to find the answer.

42 is 56% of 75, hence 3 is the answer.

Fahad Khan said: (Oct 11, 2012)  
@Sarwat.

First assume that the number is x so.
Their 30% is x*30/100 which is equal to 180 i.e. x*30/100 = 180.

So x=60 again 3 times of that number is 180 and their 15% is equal to 180*15/100 = 27 that's the answer.

Njk said: (Nov 23, 2012)  
Suraj and Radhika's answers are super. But Suraj answer is little confusing.

Aravind said: (Dec 13, 2012)  
Why we put equate here between x+9 = 56/100* (x+9+x).

Sri Ram said: (Dec 14, 2012)  
Took 25 minutes to crack the stupid nut. The commonly confused place is (56%o of TOTAL marks so it is written as (x+9) +x where x is marks scored by one person and x+9 is marks scored by the later.

Aniket said: (Feb 16, 2013)  
I need help on following question:

A candidate who gets 50% of total marks gets 100 marks more than the pass marks. Another candidate who gets 70% of the first candidates marks failed by 50 marks. How much percent a student needs to pass the exam?

Spt said: (May 8, 2013)  
@Aniket.

Let total mark be x.

50% of x--> (50/100)*x = (1/2)x

Therefore (1/2)x-100 = P --(1). Here P is the pass mark.

70% of 1st candidate marks--> 70% of (1/2)x
(7/20)x.

Therefore (7/20)x+50 = P --(2).

Then equating (1) and (2) we get,
(1/2)x-100 = (7/20)x+50 ==> 3x = 3000.
x = 1000.

Then 50% of x
(50/100)*1000 = 500.

500-100 = 400;
400 is the Answer.

Ganesh said: (Jul 10, 2013)  
very 1 stape is just to calculate total marks in each option,
suppose, I'm choosing 39 30 then total marks are 69 which is 100% if u calculate 56% of 69 i.e 56*69/100 you get 38.64 which is not in option. so leave it there.

if you're taking 42 33 then total marks are 75 which is 100% and 56% of 75 is 42 hence option C is correct.

though it is lengthy procedure, we can choose the option for calculation by little thinking before solving it.

Jvn said: (Aug 9, 2013)  
Percentage diff is 12%.

So 12% is equal to 9 marks.

So for 56% whats the marks(x).

We get x = 56*9/12.

= 42.

Kumudha said: (Aug 16, 2013)  
I couldn't understand the question. In question it is given. No.of student = 2 and one secured 9 marks more than other. Upto this clear I'm. What's the meaning of, 56% of their sum of their mark.

Neelu said: (Nov 12, 2013)  
Let mark of person A = x.
Mark of person B = x+9.

Total marks secured by both A & B = x+(x+9).
Since %mark of person B = 56/100(x+(x+9)).
Therefore x+9 = 56/100(x+(x+9)).

x+9 = 14/25(2x+9).
25(x+9) = 14(2x+9).
25x+225 = 28x + 126.
28x-25x = 225 - 126.

3x = 99.
x = 99/3.
x = 33.

Hence mark of person A = 33.
Mark of person B = 33+9 = 42.

Jenda Fayaz said: (Jan 3, 2014)  
The diff two students marks % is 9.

56%-44% = 9 marks.
Then 12% = 9 marks.

Then 100% = 9*100/12 = 75 marks.

You have to check the answer is 42,33.

Shrikant Sir said: (Jan 11, 2014)  
Just observe the question, you will find.

We assume total of both marks is 100 %.

1) 100-56 = 44.
2) 56-44 = 12.

3) It means 12% = 9 marks.
Than 44% = ?

You will get 33 marks.
4) Same way.

12% = 9 marks.
56% = ?

You will get 42 marks.

Sagar said: (Apr 15, 2014)  
How its Came?

x+9 = 14/25(2x+9).

Vignseh said: (Apr 18, 2014)  
Let you considered the to students are A and B.

The mark of A is = x.
Then the mark of B is = x+9.

And the B scored 56% of sum of their total marks of both A and B.

So the mark of B can said by,
B = 56% of (A+B).

So,
x+9 = 56/100 (x+x+9).

Now you solve the equation and find the x value.
The x value is equal to A mark.
And add the 9 with x value for the B's mark.

Being Sunil said: (May 9, 2014)  
Guys, its simple... just equalize 1% as under:

=> (x+9)/56 = x/44.
=> (x+9)/14 = x/11 (denominator divided by 4 to simplify).
=> 14x-11x = 99 (cross multiply & side changed for x's value).
=> x = 99/3 = 33 (one score).

Other score = 33 + 9 = 42.
So answer is (C) 42,33... :-).

Swaminathan Vembu said: (Jul 2, 2014)  
If I simplify the given statement and assemble it numerically what do I have ?

A. 39 = 56/100 * 69 => Not True.

B. 41 = 56/100 * 73 => Not True.

C. 42 = 56/100 * 75 => True.

D. 43 = 56/100 * 77 => Not True.

Therefore the correct answer is C.

Anusha said: (Sep 24, 2014)  
Solution: Let 1st person marks = x.
2nd person marks = x-9.

From question 1st person marks is 56% of sum of their marks.

x = 56/100(x+x-9).

x = 56/100(2x-9).

x = (56*2x)/100 - (56*9)/100.

x((56*20/100)-1) = (56*9)/100.

x = 42.

Rahul said: (Sep 28, 2014)  
This is how I understood :

x = y+9.
x = 0.56(x+y).

x-y = 9.
x-0.56x-0.56y = 0.

0.44x-0.56y = 0.
x = (0.56/0.44)y.
x = (56/44)y.

(56/44)y - (44/44)y = 9.
(12/44)y = 9.
y = 9*44/12.
y = 3/4*44=3*11=33.
y = 33.

x = 33+9.
x = 42.

Anu said: (Nov 21, 2014)  
=> 25(x + 9) = 14(2x + 9).
=> 3x = 99.

How it became this?

Suseela said: (Dec 27, 2014)  
Please, don't confuse with these calculations, my advice is to go by options because, we have two exam marks.

And in question they have asked about the 56% of sum of two exam marks. So go by this way.

Check options:

1. 56/100*69 = 38.
2. 56/100*73 = 40.88.
3. 56/100*75 = 42.
4. 56/100*77 = 43.12.

So the option 3 answer matches with the option 3 in the question. The correct answer is option 3. i.e.. 42, 33.

Suren said: (Jan 22, 2015)  
Its very simple.

What is the % difference 12% mark difference 9 if 12% = 9; 56%=?

56*9/12 = 42 which is highest mark.

So 42-9 = 33.

Answer is 42, 33.

Sneha said: (Jan 22, 2015)  
He got 9 marks.

Kavi said: (Jul 6, 2015)  
How come x+x+9?

Debasis Biswas said: (Jul 11, 2015)  
Correct answer is 42, 33.

Chandan Pandit said: (Sep 8, 2015)  
Please clear this.

Tukuna Behera said: (Sep 12, 2015)  
Dear @Chandan it is very simple,

Two students total mark in percentage is 56% that mention in the question.

If we discuss this line the result is x+y = 56%.

But the question says one of them secured 9 marks than other.

So we assume one student is (x+9) and other is x.

Here x+9 means x+9 is secured 9 marks extra than x.

Now if we try to find out the value of x from x+9. If we find out the x output then we must find out both students mark.

x+9 = 56(x+9+x)/100 [here we write 56(x+9+x) means both students percentage is 56%].

x+9 = 14(x+9+x)/25.
25(x+9) = 14(2x+9).

3x = 99 [25x+225 = 28x+126 => 28x-25x = 225-126 =>3x = 99].

x = 33[x = 99/3 => 33].

Now the original output is:

Two students are: x, (x+9).

1st student's mark is: x = 33.

2nd student is secured 9 marks than 1st student => (x+9) = 33+9 = 42.

Output option is C: 42, 33.

2Ku said: (Sep 12, 2015)  
Dear @Kavi,

Here we assume that two students mark, one is secured than other in 9 marks.

So let 1st student is x.

2nd student is x+9 [2nd student is secured 9 marks than 1st].

Ravi said: (Nov 9, 2015)  
Option method is too easy and fastest way to solve this question.

Mazher said: (Nov 28, 2015)  
@Tukuna Behera.

Why did we take the 25 to the R.H.S, that's the only step I did not understand, help please, or any one, why did we take the 25 to the Right Hand Side?

Sandipwaghmare said: (Feb 10, 2016)  
@Sawant.

= 30/100*x = 180*100/30.

x = (180*100/30)100/30.

x = 270.

Babajan said: (Mar 7, 2016)  
Which formula of percentage are used in this question?

Arshad said: (May 2, 2016)  
Try by Back Solving Method:

Lets try c: 42, 33 so it means total marks are : 42 + 33 = 75 Marks.

Let's try to find out 56 % from marks given in option C.

42 * 100/75 = 56 %

33 * 100/75 = 44 %.

So option C is the correct answer .

Uto Hussain said: (Jun 25, 2016)  
Let's say 'x' is the mark of the first person.

Then from the question, the mark of a 2nd person is 'x + 9'.

Since the percentage of the 2nd person is given i.e. 56%.

We can solve the x value using the below formula.

Per% of 2nd person = mark of 2nd person * 100/ (total marks i.e x + x + 9).

56 = ((x + 9) *100) / (x + x + 9).

Prudhvira said: (Jul 11, 2016)  
Please, explain in a simple way.

Shubham Thakur said: (Jul 14, 2016)  
It's very simple.

If 1student got 56% that means other got 44%.
56 - 44 = 12%.
Fr 12%~9 is there,
So, for 100% ~99.

Only pair which satisfies it is 39 & 30.
That it.

Anirudh Razdan said: (Jul 26, 2016)  
Why do we equate it to x + 9? Why not x?

Bgnr said: (Aug 5, 2016)  
I am confused it says the sum of their marks. Then it should be like this.

x + x + 9 = 56/100.

Can anyone explain this?

Roja said: (Aug 17, 2016)  
Thank you @Ganesh.

Piyush Pankaj said: (Aug 18, 2016)  
Thanks @Neelu.

Karthikeyan said: (Aug 29, 2016)  
Can you please explain why we keep in x + 9 on the left side?

Durgao said: (Sep 2, 2016)  
Thank you @ Radhika.

Santanu said: (Sep 4, 2016)  
56% - 44% = 9.
100% = 75.

Which total makes 75. That's it.

Satheeshkumar said: (Sep 8, 2016)  
How 25 came? Please explain that.

Archana Gaikwad said: (Sep 16, 2016)  
56% - 44 = 9.

But please explain 100% = 75.

& How 25 come?

Mohan said: (Sep 19, 2016)  
To my understanding.

Student 2 score = x.
Student 1 score 9 marks more than student 2 = x + 9 which is 56 percent of the total marks(x + x + 9) right.

x + 9 = 56%(x + x + 9).

Solving the above equation we will get x = 33 which is student 2 mark.

Student 1 has scored 9 marks more than student 2 so 33 + 9 = 42.

Ishita said: (Oct 16, 2016)  
I can not understand the question. Please someone explain me.

Sujay said: (Oct 18, 2016)  
Let their marks be(x + 9)and x.

Then, x+9 =56/100(x + 9 + x),
= 25(x + 9)= 14(2x + 9),
= 3x = 99,
x = 33.

So,there marks are 42 and 33.

Sunil said: (Oct 21, 2016)  
What calculation do for this 25(x + 9) = 14(2x + 9)?

Sai said: (Nov 25, 2016)  
Please explain me in a simple way.

Sangay Tenzin said: (Dec 23, 2016)  
25(x + 9) = 14(2x +9).

From where this 25 & 14 come from?

Could you explain me clearly, I am confuse with that.

Sangay Tenzin said: (Dec 23, 2016)  
When I divide 56/100 by 4 I got 14/25. But I did not know from where this 4 come from?

So please help me to get it.

Umang Gandhi said: (Dec 24, 2016)  
Let two student a&b.

a scores 9 marks more than b and have 56%.
a = 56%.
b = 100-56 = 44%,
56% = 9 + 44%,
12% = 9.

Let total marks be x.
12%X = 9,
(12/100) * x = 9,
x = 75.

Sum of both a and b = 75.
We check option which satisfies above condition = 42, 33.

Borra Vamsi Krishna said: (Jan 6, 2017)  
Please explain in simple way.

Megha said: (Feb 7, 2017)  
In an exam, 5%of the application were found ineligible &85% of the eligible candidates belongs to general category. If 4275 eligible candidates belonged to other categories, then how much candidates applied for the exam?

Please answer this question.

Dinesh D said: (Feb 19, 2017)  
@Aniket.

Let the total number of candidates who applied be x.
Ineligible candidates = 0.05x.
Eligible candidates = x-0.05x = 0.95x.
General category candidates who are eligible = (0.95x)*0.85 = 0.8075x.
Other category candidates who are eligible = 4275.

Then x = 0.05x + 4275+0.8075x.
= 0.8575x + 4275.
0.1425x = 4275.
x = 30000.

Purwa said: (Mar 17, 2017)  
Great explanation, thanks @Neelu.

Alikarai said: (Apr 1, 2017)  
I need help for this question. Kindly help me.

If the money is devalued by 4% find the% increase in money that will have to spent to buy a particular article.

Bhusan said: (Apr 5, 2017)  
Hi, can you please explain it came?

Then, x + 9 = 56 (x + 9 + x)
100
25(x + 9) = 14(2x + 9).

If we divide with 4 by 56/100 then the answer is 25 and 14. My question is how 4 came into picture?

Albert Einstein said: (Apr 8, 2017)  
Let their marks be (x + 9) and x.

Then, x + 9 = 56/100(x + 9 + x).
25(x + 9) = 14(2x + 9),
3x = 99,
x = 33.

So, their marks are 42 and 33.

Hari said: (Apr 16, 2017)  
25(x+9) = 14(2x+9).

Why 25 came here? Explain briefly.

Raja said: (May 5, 2017)  
Explain it.

In an exam, 5%of the application were found ineligible &85% of the eligible candidates belongs to general category. If 4275 eligible candidates belonged to other categories, then how much candidates applied for the exam?

90% application is a general category and ineligible. So balance 10%are other categories and it's 4275 application. So 10%is equal to 4275 then 100% is equal to 42750 application.

Nikhila said: (Jun 8, 2017)  
Where you get 25 and 14? Please tell me.

Sonu said: (Jun 22, 2017)  
A family consumes 25 kg rice and 9 kg wheat per month spends Rs. 350. The price of rice is 20% of the price of the wheat. If the price of wheat is increased by 20% then, find the % reduction in consumption of rice, if it has the same amount to spend.

Can anyone answer it?

Hariharan E said: (Jun 26, 2017)  
Please explain how to get the answer?

Vishwa said: (Jul 18, 2017)  
@Hariharan.

Try to understand.

Assume the first person as A second person as B.
A = 56%.
B = 44%.
Now just take the difference between their%.
A-B=12%.
In the problem itself, they have given that A is 9 more than B.
This 9 marks is nothing but that difference 12%.
Hence 12%-9.
56%-?=42=A.
B=A-9=42-9=33.

Shivashankar said: (Jul 30, 2017)  
Thank you @Aparna.

Asif Husain Jafri said: (Aug 12, 2017)  
First, sum all the option and find its 56%.
in option 42+33=75.
75 of 56% =42.
42-9=33.

Bismah Hanif said: (Aug 15, 2017)  
How? Please explain in detail. @Asif Husain Jafri.

Aman Tomar said: (Aug 26, 2017)  
Hello Guys
Simple method.

A=x+9,
B=x,
x+9=56%(x+x+9),
x+9=56/100(2x+9),
x=33,
A=33+9=42.
B=33.

Gyanajyoti said: (Aug 26, 2017)  
Bdw why (x+9+w) became multiple with 56/100?

Lingeswaran said: (Aug 31, 2017)  
Thanks @Aman Tomar.

Vinaya said: (Sep 23, 2017)  
Thanks @Tukuna.

Jajjo said: (Nov 12, 2017)  
How you can take 25 at lhs and 14 rhs?

Waqar said: (Dec 12, 2017)  
Thanks @Ashok.

Nishant said: (Jan 7, 2018)  
It's actually very simple!! If 1 student got 56%, then other student % must be 100-56%=44%.

Now 56%- 44%=12%.
12%=9(the difference between the marks of both the students).

You can solve it now!

Sushmitha said: (Apr 30, 2018)  
25(x+9) = 14(2x+9) how its came?

Please explain this step.

Kalyan said: (May 25, 2018)  
Let both of them be A and B.
Given A= 9+X and B = x.
Also A = 56% of their total marks;
So, A = 56/100 * (9+x+x).

Where A= 9+x.
By equating we can get x value 33.

A = 33+9 = 42.

Vel7 said: (Jun 3, 2018)  
Take option c. 42, 33.
Then 42+33=75 so, 75= 100%.
7.5=10%.
0.75=1%.

We calulate 56% 1%= 0.75.
56%=0.75*56= 42
Difference 9. So 42-9=33.

Sai said: (Jul 8, 2018)  
We can easily say by seeing option also for time-saving.

Take total Mark's =100
One's mark is 56 % of sum
So here the sum is 100
56% of 100 is 56
And remaking Mark's is 44
So its in the ratio of 44:56
We can take 11*4:14*4
11x:14x
So the Marks are multiple of 11 and 14.

Thank you.

Prakhar Maheshwari said: (Jul 16, 2018)  
Answer is C.

I have directly used option to get the answer.

So, 42/75*100 =56%; (42+33 =75).

Vasu said: (Jul 29, 2018)  
How it is 56-44/100=12?

Girish P said: (Aug 5, 2018)  
Easiest way to solve this is as follows:

The total percentage of marks is 56%,
so divide 56 by 2,
You get 33, 1%=6 marks, the student has scored 9 marks more so,
33+9=42, the other student marks will be 9 marks less so simple,
42-9=33.
ANSWER=42 & 33.

Rohan said: (Aug 15, 2018)  
@Hiren Savalia.

Can you elaborate your method?

Mukul said: (Aug 22, 2018)  
Let's take x, x+9; of their marks.

x=44/100*(x+x+9) or -+9=56/100*(x+x+9).
Solve; eq x =33. And another x+9.
33+9=42.

Roopsingh said: (Aug 31, 2018)  
How come 56/100? Please explain in detail.

Dsr said: (Sep 23, 2018)  
Good explanation, Thanks all.

Nagesh V said: (Oct 25, 2018)  
Thank you @Shrikant.

Shweta said: (Dec 8, 2018)  
Best explanation, Thanks @Girish P.

Victory said: (Mar 5, 2019)  
How come 25 and 14? Please tell me.

Joseph said: (Apr 16, 2019)  
Let marks be of st A=x, and st B = x+9.
Then,

x+9=56/100(x+x+9).
100(x+9)=56(x+x+9).
100x+900x=56x+56+504,
100X+900= 112x+504,
112x-100x=900-504.
12x=396,
x=396/12,
x=33,
x+9=33+9 = 42.

Akshita said: (Jun 23, 2019)  
@Vel.

Let x be the student who scores 56% marks.
That is, x = y+9.

X = 56% marks of the sum of their marks.
=> Y + 9 = 56% of sum of their marks --> (i)
And x + y = sum of their marks.

Putting the value of x,
(Y+ 9) + y = sum of their marks
2y + 9 = sum of their marks --> (ii)

Now putting the value of (ii) into (i):
Y + 9 = (56/100) ( 2Y+ 9).
3y = 99,
Y = 33, X = 42.

Amit Katnoria said: (Aug 31, 2019)  
Can't we assume the mark's of another person :-X & those who have less:-X-9?

Likewise;
(X+X-9)*56/100 = X.

Sailu said: (Nov 20, 2019)  
Let student 1 = x.
2nd student secured 9marks more = (x+9).

This marks = 56%(total sum marks).

x+9 = 56/100(x+x+9)
100(x+9) = 56(2x+9)
100x+900 = 112x+504
900-504 = 112x-100x
396 = 12x
x = 396/12=33.
x = 33.

x+9 = 33+9 = 42.
(33, 42).

Ramana said: (Dec 25, 2019)  
Why we add x and x+9?

Md Attaullah said: (Jan 16, 2020)  
As per my method, the Solution is;
Gap in marks= 9.
Gap in percentage= 12%,
1st student marks = 56% = 56/12 * 9 = 42.
2nd student marks = 44% = 44/12 * 9 = 33.

Deepika said: (Feb 12, 2020)  
@Anthea. You do by simply dividing 56/100 by least divisible 2 then you got answer 14/25. Hope it's clear !

Pariki Pramodh said: (Apr 17, 2020)  
A simple Answer.

Here given 2 students (assume A&B)
* One of the student(A) marks is = 56%
* And remaing student (B) marks is =44% (100%-56%)
Then, the gap between them is=12% (56-44).

So we know that one person got more marks than another person = 9mrks.

So,
A.
12%-----------> 9mrks.
56%----------> ?
Then {56*9/12}.
Ans 42.

Similarly for B;
12%-------> 9mrks
44%-------> ?
=> {44*9/12} = 33.

Ashwin said: (Apr 23, 2020)  
@Sarwat

30%of number 180,
30/100*y=180.
y=600.
15%of3(number) =? .
15/100*3(600) =2700.

Ruhi said: (Apr 27, 2020)  
Total 100%.

One got 56 then the other got 44.
Diff 12%=9 (one got 9 marks more),
56%=42.
And 44%=33.

Sanjay said: (May 22, 2020)  
@All.

Simply, the solution is;

56 % and balance is 44, Right!
56/100 = 9,
56 - 44 / 100 = 9,
It will give you 75.
THEN,
56/100 X 75 = 42.
44/100 X 75 = 33.

Swathi Krishna said: (Jun 9, 2020)  
Given,

One of them secured 9 Mark's more than other.

And one person got 56%, the second person got 100-56=44.

Difference 56 - 44 = 12, So 12% is 9 Mark's.

12------------>9Mark's
56------------>?
56 * 9/12=42.

One person got 42 Mark's.
Another person got 42 - 9 = 33marks.

Harsha said: (Aug 1, 2020)  
Why we make x+x+9 their? I am not getting that, Anyone explain me.

Tiki said: (Aug 5, 2020)  
Thanks @Neelu.

Ntb said: (Aug 26, 2020)  
which formula did we use in this? Anyone explain me, please.

Raveesh R said: (Sep 10, 2020)  
42+33 = 75.
42/75*100 = 56%.

Vaishnavi said: (Sep 20, 2020)  
How can you guys are multiplying with x+x+9?

Is 56% is total marks scored by both of 2 students.

I am getting confused. Please explain.

Anju said: (Oct 29, 2020)  
Listen, 56% of SUM OF THEIR MARKS is equal to 2nd person mark.

So, we can simplify 56/100.
By simplifying it we get 14/25.

So we can say that mark of 2nd person is 14 and the first one is 11(we get 11 by subtracting 25-14).

We know that 14-11 is 9 (it's already given in the answer).
That is 3=9.
So, 1=3.

Therefore 14*3 = 42 and 11*3 = 33.

Anomie said: (Nov 13, 2020)  
x+9=56/100(2x+9),
How did you reach to this step?

How can you equate both student marks although they have a difference of 9 marks
L.H.S = marks of 2nd student
R.H.S = marks in the percentage of 1st student out of the total sum of the marks scored by both of them.

Please anyone explain it.

Geetha said: (Nov 23, 2020)  
Where does this 25 and 14 in equation come? Please explain about it.

Gaurav said: (Jan 17, 2021)  
@Geetha.

It comes 25/14 when you divide 56/100.

Nisma said: (Jan 19, 2021)  
2 numbers are (x) and (x+9).
Now,
(x+9) =56% of (x+x+9),
=(2x+9)56%.

Now open brackets
x+9 = 112x/100 + 504/100,
9 - (504/100 ) = (112x-100x)/100,
(900-504)/100= 12x /100,
396/100 = 12x/100.
>> 396 = 12x.
396/12 = x
33=x,
So 2 digits are:
x = 33,
x+9 = 42.

Pawan said: (Mar 30, 2021)  
Answer = C.

1st students marks percentage = 56%,
2nd percentage= 100-56 = 44%,
Difference between marks = 9,
Difference between percentage=56-44 = 12%.
9 = 12% ->1 = 0.75 ->100 = 75(total marks).
56% = 0.75X56 = 42 ,44% = 0.75X44 = 33.

Jeeva said: (May 11, 2021)  
@Vel.

Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.

Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.

Balaganesh said: (May 14, 2021)  
@Pawan.

From the QN, Sum of their mark % is 56%.

Diksha said: (Jun 30, 2021)  
Understand the statement :

One of them secured 9 marks more than the other.
So it is (9 + x) , right ?

Next part is " 56% of the sum of their marks"
So here, sum is (x + 9 + x).
And its 56% is (56/100) * (x + 9 + x).

So now, the important part is " .. 9 marks more than the other AND HIS MARKS WAS 56% of ... "

In this line, it says HIS Marks, so whose marks it is ?? It is the marks of ( 9 + x ).
(9 + x ) is the 56% of their sum.

Because of this line, we have equal to symbol in the equation,

So the equation is : (9 + x) = (56/100) * (x + 9 + x).

Naina said: (Jul 22, 2021)  
Thanks @Diksha.

Dhiren said: (Aug 26, 2021)  
Simple way using ratio.

56 : 44.
i.e 14:11.
33 is divisible by 11 so the answer is C.

Soham Garai said: (Sep 7, 2021)  
Let one student obtain x marks.

So, another obtained x+9 marks.

According to question.

X+9 = 56/100'- (2x+9).

By cross multiplying.

3x = 99.
x = 33.

So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.

Soham Garai said: (Sep 7, 2021)  
As one got X marks another X+9 so, the sum of both is 2x+9.

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