Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
153 comments Page 1 of 16.

Moli said:   2 weeks ago
Total =100
F= 56%
S = ?.

So,
X = 100 - 56 = 44.
44 - 9 = 33.
(15)

AVINASH KUMAR said:   8 months ago
A and B is there;

A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
(33)

Shakthi said:   8 months ago
Let one student obtain x marks.
So, another obtained x+9 marks.
According to the question;
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
(27)

Suresh said:   10 months ago
Total mark% = 56.
Then the remaining percentage= 100 - 56 = 44%.
Difference percentage = 56-44 = 12%.
Then the difference mark= 9.
So, 12 percentage = 9 then what percent = 56% = 42.
42-9 = 33.
(249)

Ritesh Rawal said:   1 year ago
Your explanation is simple & clear. Thank you very much @Neelu.
(19)

Arjun said:   1 year ago
Why we Equalize 56/100 (2x+9) into x+9? can anyone please explain this?
(14)

Chernet said:   2 years ago
Thanks all for giving an excellent explanation.
(7)

Dr.Mahaveer said:   2 years ago
@All.

Hello.

Simply, the solution is;

A = x+9,
B = x,
x+9 = 56%(x+x+9),
x+9 = 56/100(2x+9),
x = 33,
A = 33 + 9 = 42.
B = 33.
(33)

Aarti said:   2 years ago
Difference of the both students marks:


56% - 44% = 12%.
Difference is = 9
12% = 9
1% = 9/12
100% = 9*100/12 = 75.

Total marks = 75.

56% of total marks = 75*56/100 = 42.
42-9 = 33.
(90)

Rohit said:   2 years ago
Thank you for explaining @Rahul.
(3)


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