Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 18 of 18.
Vel said:
1 decade ago
Ok why equal sign assigned b/w x+9 and 56/100 (x+9+x) ?
(1)
Aparna said:
1 decade ago
Suppose 1 students score is 'x',then others will be 'x+9'
Now the next information is given about the student whose score is 'x+9'
Whenever in the question 'and'/'is' given put '=' sign
56% means 56/100 ,of means put multiplication sign
and sum of the marks means(x+x+9)
Now just solve the equation.
Now the next information is given about the student whose score is 'x+9'
Whenever in the question 'and'/'is' given put '=' sign
56% means 56/100 ,of means put multiplication sign
and sum of the marks means(x+x+9)
Now just solve the equation.
(1)
Ramya said:
1 decade ago
Please explain in simple way.
(2)
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