Aptitude - Percentage - Discussion

VERY EASY:

Let total marks be = 100.
F =56%.
Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.

Let total marks be =100.
F =56%.

Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.

Total mark% = 56.
Then the remaining percentage= 100 - 56 = 44%.
Difference percentage = 56-44 = 12%.
Then the difference mark= 9.
So, 12 percentage = 9 then what percent = 56% = 42.
42-9 = 33.

Obtained mark % = 56.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.

Let's say two students are X and Y.

For instance, assume that the total mark was 100. Meaning X+Y = 100.

Now, if X gets 56% of the sum of their marks which was 100, then Y must have the remaining percentage of the marks, that's 44%.

Now, compare the difference between the marks that they've obtained and the percentage that they have.

So, difference in percentage = X-Y = 56-44 = 12%
And, the difference in marks = X-Y = 9 (Because in the question it's given that one has 9 marks more than the other.)

Now, we've to find the value of 1 Unit. If you can find that you can easily solve the question.

Comparing their marks and their percentages,

12% = 9 marks.
1 Unit = 9/12.
1 Unit = 0.75.

Now multiply the value of 1 Unit by the percentage they've got.

X = 56*0.75 = 42.
Y = 44*0.75 = 33.
And their difference is also 9.

@All

Here, some people doing the wrong calculation 44-9=35 not 33. Please correct it.

Total =100
F= 56%
S = ?.

So,
X = 100 - 56 = 44.
44 - 9 = 33.

Difference of the both students marks:


56% - 44% = 12%.
Difference is = 9
12% = 9
1% = 9/12
100% = 9*100/12 = 75.

Total marks = 75.

56% of total marks = 75*56/100 = 42.
42-9 = 33.

Total = 100.
F = 56%,

Therefore;
X = 100 - 56 = 44.
44 - 9 = X = 33.

Obtained mark% = 56 and Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.