Aptitude - Percentage - Discussion

Still, I can't understand this. Please explain to me.

Let's say two students are X and Y.

For instance, assume that the total mark was 100. Meaning X+Y = 100.

Now, if X gets 56% of the sum of their marks which was 100, then Y must have the remaining percentage of the marks, that's 44%.

Now, compare the difference between the marks that they've obtained and the percentage that they have.

So, difference in percentage = X-Y = 56-44 = 12%
And, the difference in marks = X-Y = 9 (Because in the question it's given that one has 9 marks more than the other.)

Now, we've to find the value of 1 Unit. If you can find that you can easily solve the question.

Comparing their marks and their percentages,

12% = 9 marks.
1 Unit = 9/12.
1 Unit = 0.75.

Now multiply the value of 1 Unit by the percentage they've got.

X = 56*0.75 = 42.
Y = 44*0.75 = 33.
And their difference is also 9.

Let 1st student (A) marks = x.
Therefore,
2nd student (B) marks = x+9.
Now , x+9 = 56% of {(x+9)+(x)}.
=> x+9= 56/100 (x+9+x),
=> x+9 = 0.56(x+9+x),
=> x+9 = 0.56x + 0.56x + 5.04,
=> x+9 = 1.12x + 5.04,
=> x-1.12x = 9 - 5.04,
=> 0.12x = 3.96.
=> x = 3.96/0.12.
=> Marks of A = [x = 33].
Therefore, Marks of B = x+9.
=> 33+9 = 42.

Let the marks obtained by the students be a and b:

Let a = b + 9 -------->1
a = (56/100) * (a+b) ---------> 2.

From equation 1, equation 2 can be written as;

b + 9 = (0.56) * (b + 9 + b),
b + 9 = (0.56)(2b + 9).
b + 9 = 1.12b + 5.04
9 - 5.04 = 1.12b - b.
3.96 = 0.12b,
b = 3.96/0.12,
b = 33.

Then, a=b+9
a=33+9
a=42

Therefore, marks scored by a and b are 42 and 33.

Obtained mark % = 56.
Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 % = 9.
56% = x.
56*9/12 = 42.
42-9 = 33.

Let total marks be =100.
F =56%.

Therefore,
X = 100-56 = 44,
44-9 = 33,
33+9 = 42.

@All

Here, some people doing the wrong calculation 44-9=35 not 33. Please correct it.

Obtained mark% = 56 and Total mark %= 100.
Remaining % = 100 - 56 = 44%.
Difference % = 56-44 = 12%.
Then the difference mark 9.
So,
12 %=9.
56% =x.
56*9/12 =42.
42-9 = 33.

Total = 100.
F = 56%,

Therefore;
X = 100 - 56 = 44.
44 - 9 = X = 33.

Let's say X, and Y are students.

We can say Y got 44% of the total marks since X got 56%.
Percentage difference b/w X, Y is 56%- 44% = 12%.
X got 9 marks more than Y, So 9 marks are equal to 12%.
So, 1% of marks equal to, 9/12 = 0.75,
X marks are, 0.75 * 56 = 42.
Y marks are, 0.75 * 44 = 33.