Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
173 comments Page 3 of 18.
Moli said:
2 years ago
Total =100
F= 56%
S = ?.
So,
X = 100 - 56 = 44.
44 - 9 = 33.
F= 56%
S = ?.
So,
X = 100 - 56 = 44.
44 - 9 = 33.
(97)
AVINASH KUMAR said:
3 years ago
A and B is there;
A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
A + B = 100.
A = 56,B = 44,A - B = 12.
12%U = 9
12/100U = 9
3/25U = 9
3U = 9
1U = 3
A = 56% = 56/100,14/25U
A = 14U = 14 * 3 = 42
B = 11U = 11 * 3 = 33.
(37)
Shakthi said:
3 years ago
Let one student obtain x marks.
So, another obtained x+9 marks.
According to the question;
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
So, another obtained x+9 marks.
According to the question;
X+9 = 56/100'- (2x+9).
By cross multiplying.
3x = 99.
x = 33.
So, one obtained 33 and another obtained 33 + 9 = 42 as x+9.
(31)
Suresh said:
3 years ago
Total mark% = 56.
Then the remaining percentage= 100 - 56 = 44%.
Difference percentage = 56-44 = 12%.
Then the difference mark= 9.
So, 12 percentage = 9 then what percent = 56% = 42.
42-9 = 33.
Then the remaining percentage= 100 - 56 = 44%.
Difference percentage = 56-44 = 12%.
Then the difference mark= 9.
So, 12 percentage = 9 then what percent = 56% = 42.
42-9 = 33.
(274)
Ritesh Rawal said:
3 years ago
Your explanation is simple & clear. Thank you very much @Neelu.
(20)
Arjun said:
3 years ago
Why we Equalize 56/100 (2x+9) into x+9? can anyone please explain this?
(16)
Chernet said:
4 years ago
Thanks all for giving an excellent explanation.
(9)
Dr.Mahaveer said:
4 years ago
@All.
Hello.
Simply, the solution is;
A = x+9,
B = x,
x+9 = 56%(x+x+9),
x+9 = 56/100(2x+9),
x = 33,
A = 33 + 9 = 42.
B = 33.
Hello.
Simply, the solution is;
A = x+9,
B = x,
x+9 = 56%(x+x+9),
x+9 = 56/100(2x+9),
x = 33,
A = 33 + 9 = 42.
B = 33.
(39)
Aarti said:
4 years ago
Difference of the both students marks:
56% - 44% = 12%.
Difference is = 9
12% = 9
1% = 9/12
100% = 9*100/12 = 75.
Total marks = 75.
56% of total marks = 75*56/100 = 42.
42-9 = 33.
56% - 44% = 12%.
Difference is = 9
12% = 9
1% = 9/12
100% = 9*100/12 = 75.
Total marks = 75.
56% of total marks = 75*56/100 = 42.
42-9 = 33.
(94)
Rohit said:
4 years ago
Thank you for explaining @Rahul.
(3)
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