Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 17 of 17.
Tiki said:
5 years ago
Thanks @Neelu.
Ntb said:
5 years ago
which formula did we use in this? Anyone explain me, please.
Raveesh r said:
5 years ago
42+33 = 75.
42/75*100 = 56%.
42/75*100 = 56%.
Vaishnavi said:
5 years ago
How can you guys are multiplying with x+x+9?
Is 56% is total marks scored by both of 2 students.
I am getting confused. Please explain.
Is 56% is total marks scored by both of 2 students.
I am getting confused. Please explain.
Anju said:
5 years ago
Listen, 56% of SUM OF THEIR MARKS is equal to 2nd person mark.
So, we can simplify 56/100.
By simplifying it we get 14/25.
So we can say that mark of 2nd person is 14 and the first one is 11(we get 11 by subtracting 25-14).
We know that 14-11 is 9 (it's already given in the answer).
That is 3=9.
So, 1=3.
Therefore 14*3 = 42 and 11*3 = 33.
So, we can simplify 56/100.
By simplifying it we get 14/25.
So we can say that mark of 2nd person is 14 and the first one is 11(we get 11 by subtracting 25-14).
We know that 14-11 is 9 (it's already given in the answer).
That is 3=9.
So, 1=3.
Therefore 14*3 = 42 and 11*3 = 33.
Anomie said:
5 years ago
x+9=56/100(2x+9),
How did you reach to this step?
How can you equate both student marks although they have a difference of 9 marks
L.H.S = marks of 2nd student
R.H.S = marks in the percentage of 1st student out of the total sum of the marks scored by both of them.
Please anyone explain it.
How did you reach to this step?
How can you equate both student marks although they have a difference of 9 marks
L.H.S = marks of 2nd student
R.H.S = marks in the percentage of 1st student out of the total sum of the marks scored by both of them.
Please anyone explain it.
Geetha said:
5 years ago
Where does this 25 and 14 in equation come? Please explain about it.
Gaurav said:
5 years ago
@Geetha.
It comes 25/14 when you divide 56/100.
It comes 25/14 when you divide 56/100.
Jeeva said:
4 years ago
@Vel.
Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.
Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.
Two students x and y were appear then one get more than 9marks from the other so we take that one member as y as an assumption so y =x+9.
Here we have x and x+9 as two members. Then that x+9 's mark is 56%of sum of their marks. Hence we take (x+9) = 56% (x+ (x+9) ) = option c.
Balaganesh said:
4 years ago
@Pawan.
From the QN, Sum of their mark % is 56%.
From the QN, Sum of their mark % is 56%.
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