Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 3 of 17.
BM NAIDU said:
1 decade ago
Why we equqte x+9&(56/100(x+9+x)?
Can u please explain in simple way.
Can u please explain in simple way.
Sarwat said:
1 decade ago
30 percent of a number is 180. What is 15 percent of 3 times of the same number?
Please help me in this question.
Please help me in this question.
Suhas said:
1 decade ago
Instead of calculating using variables, use options to find the answer.
42 is 56% of 75, hence 3 is the answer.
42 is 56% of 75, hence 3 is the answer.
Fahad khan said:
1 decade ago
@Sarwat.
First assume that the number is x so.
Their 30% is x*30/100 which is equal to 180 i.e. x*30/100 = 180.
So x=60 again 3 times of that number is 180 and their 15% is equal to 180*15/100 = 27 that's the answer.
First assume that the number is x so.
Their 30% is x*30/100 which is equal to 180 i.e. x*30/100 = 180.
So x=60 again 3 times of that number is 180 and their 15% is equal to 180*15/100 = 27 that's the answer.
NJK said:
1 decade ago
Suraj and Radhika's answers are super. But Suraj answer is little confusing.
Aravind said:
1 decade ago
Why we put equate here between x+9 = 56/100* (x+9+x).
Sri Ram said:
1 decade ago
Took 25 minutes to crack the stupid nut. The commonly confused place is (56%o of TOTAL marks so it is written as (x+9) +x where x is marks scored by one person and x+9 is marks scored by the later.
Aniket said:
1 decade ago
I need help on following question:
A candidate who gets 50% of total marks gets 100 marks more than the pass marks. Another candidate who gets 70% of the first candidates marks failed by 50 marks. How much percent a student needs to pass the exam?
A candidate who gets 50% of total marks gets 100 marks more than the pass marks. Another candidate who gets 70% of the first candidates marks failed by 50 marks. How much percent a student needs to pass the exam?
SpT said:
1 decade ago
@Aniket.
Let total mark be x.
50% of x--> (50/100)*x = (1/2)x
Therefore (1/2)x-100 = P --(1). Here P is the pass mark.
70% of 1st candidate marks--> 70% of (1/2)x
(7/20)x.
Therefore (7/20)x+50 = P --(2).
Then equating (1) and (2) we get,
(1/2)x-100 = (7/20)x+50 ==> 3x = 3000.
x = 1000.
Then 50% of x
(50/100)*1000 = 500.
500-100 = 400;
400 is the Answer.
Let total mark be x.
50% of x--> (50/100)*x = (1/2)x
Therefore (1/2)x-100 = P --(1). Here P is the pass mark.
70% of 1st candidate marks--> 70% of (1/2)x
(7/20)x.
Therefore (7/20)x+50 = P --(2).
Then equating (1) and (2) we get,
(1/2)x-100 = (7/20)x+50 ==> 3x = 3000.
x = 1000.
Then 50% of x
(50/100)*1000 = 500.
500-100 = 400;
400 is the Answer.
Ganesh said:
1 decade ago
very 1 stape is just to calculate total marks in each option,
suppose, I'm choosing 39 30 then total marks are 69 which is 100% if u calculate 56% of 69 i.e 56*69/100 you get 38.64 which is not in option. so leave it there.
if you're taking 42 33 then total marks are 75 which is 100% and 56% of 75 is 42 hence option C is correct.
though it is lengthy procedure, we can choose the option for calculation by little thinking before solving it.
suppose, I'm choosing 39 30 then total marks are 69 which is 100% if u calculate 56% of 69 i.e 56*69/100 you get 38.64 which is not in option. so leave it there.
if you're taking 42 33 then total marks are 75 which is 100% and 56% of 75 is 42 hence option C is correct.
though it is lengthy procedure, we can choose the option for calculation by little thinking before solving it.
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