Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
171 comments Page 18 of 18.
Krishnaa Kumari said:
3 weeks ago
Total marks = 100%.
X = 56%.
Y = 100-56.
= 44%.
Now the difference marks between X and Y.
= (56-44)%,
= 12%.
Now,
12% = 9,
1% = 9÷12,
56%= 9÷12 × 56,
= 42.
Next;
Y = 44%.
12% = 9.
1% = 9÷12,
44%= 9÷12 × 44,
= 33.
X = 56%.
Y = 100-56.
= 44%.
Now the difference marks between X and Y.
= (56-44)%,
= 12%.
Now,
12% = 9,
1% = 9÷12,
56%= 9÷12 × 56,
= 42.
Next;
Y = 44%.
12% = 9.
1% = 9÷12,
44%= 9÷12 × 44,
= 33.
(13)
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