Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 4 of 17.
Jvn said:
1 decade ago
Percentage diff is 12%.
So 12% is equal to 9 marks.
So for 56% whats the marks(x).
We get x = 56*9/12.
= 42.
So 12% is equal to 9 marks.
So for 56% whats the marks(x).
We get x = 56*9/12.
= 42.
Kumudha said:
1 decade ago
I couldn't understand the question. In question it is given. No.of student = 2 and one secured 9 marks more than other. Upto this clear I'm. What's the meaning of, 56% of their sum of their mark.
Neelu said:
1 decade ago
Let mark of person A = x.
Mark of person B = x+9.
Total marks secured by both A & B = x+(x+9).
Since %mark of person B = 56/100(x+(x+9)).
Therefore x+9 = 56/100(x+(x+9)).
x+9 = 14/25(2x+9).
25(x+9) = 14(2x+9).
25x+225 = 28x + 126.
28x-25x = 225 - 126.
3x = 99.
x = 99/3.
x = 33.
Hence mark of person A = 33.
Mark of person B = 33+9 = 42.
Mark of person B = x+9.
Total marks secured by both A & B = x+(x+9).
Since %mark of person B = 56/100(x+(x+9)).
Therefore x+9 = 56/100(x+(x+9)).
x+9 = 14/25(2x+9).
25(x+9) = 14(2x+9).
25x+225 = 28x + 126.
28x-25x = 225 - 126.
3x = 99.
x = 99/3.
x = 33.
Hence mark of person A = 33.
Mark of person B = 33+9 = 42.
(1)
JENDA FAYAZ said:
1 decade ago
The diff two students marks % is 9.
56%-44% = 9 marks.
Then 12% = 9 marks.
Then 100% = 9*100/12 = 75 marks.
You have to check the answer is 42,33.
56%-44% = 9 marks.
Then 12% = 9 marks.
Then 100% = 9*100/12 = 75 marks.
You have to check the answer is 42,33.
Shrikant sir said:
1 decade ago
Just observe the question, you will find.
We assume total of both marks is 100 %.
1) 100-56 = 44.
2) 56-44 = 12.
3) It means 12% = 9 marks.
Than 44% = ?
You will get 33 marks.
4) Same way.
12% = 9 marks.
56% = ?
You will get 42 marks.
We assume total of both marks is 100 %.
1) 100-56 = 44.
2) 56-44 = 12.
3) It means 12% = 9 marks.
Than 44% = ?
You will get 33 marks.
4) Same way.
12% = 9 marks.
56% = ?
You will get 42 marks.
Sagar said:
1 decade ago
How its Came?
x+9 = 14/25(2x+9).
x+9 = 14/25(2x+9).
Vignseh said:
1 decade ago
Let you considered the to students are A and B.
The mark of A is = x.
Then the mark of B is = x+9.
And the B scored 56% of sum of their total marks of both A and B.
So the mark of B can said by,
B = 56% of (A+B).
So,
x+9 = 56/100 (x+x+9).
Now you solve the equation and find the x value.
The x value is equal to A mark.
And add the 9 with x value for the B's mark.
The mark of A is = x.
Then the mark of B is = x+9.
And the B scored 56% of sum of their total marks of both A and B.
So the mark of B can said by,
B = 56% of (A+B).
So,
x+9 = 56/100 (x+x+9).
Now you solve the equation and find the x value.
The x value is equal to A mark.
And add the 9 with x value for the B's mark.
Being Sunil said:
1 decade ago
Guys, its simple... just equalize 1% as under:
=> (x+9)/56 = x/44.
=> (x+9)/14 = x/11 (denominator divided by 4 to simplify).
=> 14x-11x = 99 (cross multiply & side changed for x's value).
=> x = 99/3 = 33 (one score).
Other score = 33 + 9 = 42.
So answer is (C) 42,33... :-).
=> (x+9)/56 = x/44.
=> (x+9)/14 = x/11 (denominator divided by 4 to simplify).
=> 14x-11x = 99 (cross multiply & side changed for x's value).
=> x = 99/3 = 33 (one score).
Other score = 33 + 9 = 42.
So answer is (C) 42,33... :-).
Swaminathan Vembu said:
1 decade ago
If I simplify the given statement and assemble it numerically what do I have ?
A. 39 = 56/100 * 69 => Not True.
B. 41 = 56/100 * 73 => Not True.
C. 42 = 56/100 * 75 => True.
D. 43 = 56/100 * 77 => Not True.
Therefore the correct answer is C.
A. 39 = 56/100 * 69 => Not True.
B. 41 = 56/100 * 73 => Not True.
C. 42 = 56/100 * 75 => True.
D. 43 = 56/100 * 77 => Not True.
Therefore the correct answer is C.
Anusha said:
1 decade ago
Solution: Let 1st person marks = x.
2nd person marks = x-9.
From question 1st person marks is 56% of sum of their marks.
x = 56/100(x+x-9).
x = 56/100(2x-9).
x = (56*2x)/100 - (56*9)/100.
x((56*20/100)-1) = (56*9)/100.
x = 42.
2nd person marks = x-9.
From question 1st person marks is 56% of sum of their marks.
x = 56/100(x+x-9).
x = 56/100(2x-9).
x = (56*2x)/100 - (56*9)/100.
x((56*20/100)-1) = (56*9)/100.
x = 42.
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