Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
173 comments Page 10 of 18.

Suseela said:   1 decade ago
Please, don't confuse with these calculations, my advice is to go by options because, we have two exam marks.

And in question they have asked about the 56% of sum of two exam marks. So go by this way.

Check options:

1. 56/100*69 = 38.
2. 56/100*73 = 40.88.
3. 56/100*75 = 42.
4. 56/100*77 = 43.12.

So the option 3 answer matches with the option 3 in the question. The correct answer is option 3. i.e.. 42, 33.

Sneha said:   1 decade ago
He got 9 marks.

Kavi said:   1 decade ago
How come x+x+9?

Debasis Biswas said:   1 decade ago
Correct answer is 42, 33.

Chandan pandit said:   1 decade ago
Please clear this.

2ku said:   1 decade ago
Dear @Kavi,

Here we assume that two students mark, one is secured than other in 9 marks.

So let 1st student is x.

2nd student is x+9 [2nd student is secured 9 marks than 1st].

Ravi said:   1 decade ago
Option method is too easy and fastest way to solve this question.

Mazher said:   10 years ago
@Tukuna Behera.

Why did we take the 25 to the R.H.S, that's the only step I did not understand, help please, or any one, why did we take the 25 to the Right Hand Side?

SandipWaghmare said:   10 years ago
@Sawant.

= 30/100*x = 180*100/30.

x = (180*100/30)100/30.

x = 270.

Babajan said:   10 years ago
Which formula of percentage are used in this question?


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