Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
170 comments Page 10 of 17.

Debasis Biswas said:   1 decade ago
Correct answer is 42, 33.

Chandan pandit said:   10 years ago
Please clear this.

2ku said:   10 years ago
Dear @Kavi,

Here we assume that two students mark, one is secured than other in 9 marks.

So let 1st student is x.

2nd student is x+9 [2nd student is secured 9 marks than 1st].

Ravi said:   10 years ago
Option method is too easy and fastest way to solve this question.

Mazher said:   10 years ago
@Tukuna Behera.

Why did we take the 25 to the R.H.S, that's the only step I did not understand, help please, or any one, why did we take the 25 to the Right Hand Side?

SandipWaghmare said:   10 years ago
@Sawant.

= 30/100*x = 180*100/30.

x = (180*100/30)100/30.

x = 270.

Babajan said:   9 years ago
Which formula of percentage are used in this question?

Arshad said:   9 years ago
Try by Back Solving Method:

Lets try c: 42, 33 so it means total marks are : 42 + 33 = 75 Marks.

Let's try to find out 56 % from marks given in option C.

42 * 100/75 = 56 %

33 * 100/75 = 44 %.

So option C is the correct answer .

Uto hussain said:   9 years ago
Let's say 'x' is the mark of the first person.

Then from the question, the mark of a 2nd person is 'x + 9'.

Since the percentage of the 2nd person is given i.e. 56%.

We can solve the x value using the below formula.

Per% of 2nd person = mark of 2nd person * 100/ (total marks i.e x + x + 9).

56 = ((x + 9) *100) / (x + x + 9).

Prudhvira said:   9 years ago
Please, explain in a simple way.


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