Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option
Explanation:
Let their marks be (x + 9) and x.
| Then, x + 9 = | 56 | (x + 9 + x) |
| 100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Discussion:
170 comments Page 9 of 17.
Sagar said:
1 decade ago
How its Came?
x+9 = 14/25(2x+9).
x+9 = 14/25(2x+9).
Vignseh said:
1 decade ago
Let you considered the to students are A and B.
The mark of A is = x.
Then the mark of B is = x+9.
And the B scored 56% of sum of their total marks of both A and B.
So the mark of B can said by,
B = 56% of (A+B).
So,
x+9 = 56/100 (x+x+9).
Now you solve the equation and find the x value.
The x value is equal to A mark.
And add the 9 with x value for the B's mark.
The mark of A is = x.
Then the mark of B is = x+9.
And the B scored 56% of sum of their total marks of both A and B.
So the mark of B can said by,
B = 56% of (A+B).
So,
x+9 = 56/100 (x+x+9).
Now you solve the equation and find the x value.
The x value is equal to A mark.
And add the 9 with x value for the B's mark.
Being Sunil said:
1 decade ago
Guys, its simple... just equalize 1% as under:
=> (x+9)/56 = x/44.
=> (x+9)/14 = x/11 (denominator divided by 4 to simplify).
=> 14x-11x = 99 (cross multiply & side changed for x's value).
=> x = 99/3 = 33 (one score).
Other score = 33 + 9 = 42.
So answer is (C) 42,33... :-).
=> (x+9)/56 = x/44.
=> (x+9)/14 = x/11 (denominator divided by 4 to simplify).
=> 14x-11x = 99 (cross multiply & side changed for x's value).
=> x = 99/3 = 33 (one score).
Other score = 33 + 9 = 42.
So answer is (C) 42,33... :-).
Swaminathan Vembu said:
1 decade ago
If I simplify the given statement and assemble it numerically what do I have ?
A. 39 = 56/100 * 69 => Not True.
B. 41 = 56/100 * 73 => Not True.
C. 42 = 56/100 * 75 => True.
D. 43 = 56/100 * 77 => Not True.
Therefore the correct answer is C.
A. 39 = 56/100 * 69 => Not True.
B. 41 = 56/100 * 73 => Not True.
C. 42 = 56/100 * 75 => True.
D. 43 = 56/100 * 77 => Not True.
Therefore the correct answer is C.
Anusha said:
1 decade ago
Solution: Let 1st person marks = x.
2nd person marks = x-9.
From question 1st person marks is 56% of sum of their marks.
x = 56/100(x+x-9).
x = 56/100(2x-9).
x = (56*2x)/100 - (56*9)/100.
x((56*20/100)-1) = (56*9)/100.
x = 42.
2nd person marks = x-9.
From question 1st person marks is 56% of sum of their marks.
x = 56/100(x+x-9).
x = 56/100(2x-9).
x = (56*2x)/100 - (56*9)/100.
x((56*20/100)-1) = (56*9)/100.
x = 42.
Rahul said:
1 decade ago
This is how I understood :
x = y+9.
x = 0.56(x+y).
x-y = 9.
x-0.56x-0.56y = 0.
0.44x-0.56y = 0.
x = (0.56/0.44)y.
x = (56/44)y.
(56/44)y - (44/44)y = 9.
(12/44)y = 9.
y = 9*44/12.
y = 3/4*44=3*11=33.
y = 33.
x = 33+9.
x = 42.
x = y+9.
x = 0.56(x+y).
x-y = 9.
x-0.56x-0.56y = 0.
0.44x-0.56y = 0.
x = (0.56/0.44)y.
x = (56/44)y.
(56/44)y - (44/44)y = 9.
(12/44)y = 9.
y = 9*44/12.
y = 3/4*44=3*11=33.
y = 33.
x = 33+9.
x = 42.
Anu said:
1 decade ago
=> 25(x + 9) = 14(2x + 9).
=> 3x = 99.
How it became this?
=> 3x = 99.
How it became this?
Suseela said:
1 decade ago
Please, don't confuse with these calculations, my advice is to go by options because, we have two exam marks.
And in question they have asked about the 56% of sum of two exam marks. So go by this way.
Check options:
1. 56/100*69 = 38.
2. 56/100*73 = 40.88.
3. 56/100*75 = 42.
4. 56/100*77 = 43.12.
So the option 3 answer matches with the option 3 in the question. The correct answer is option 3. i.e.. 42, 33.
And in question they have asked about the 56% of sum of two exam marks. So go by this way.
Check options:
1. 56/100*69 = 38.
2. 56/100*73 = 40.88.
3. 56/100*75 = 42.
4. 56/100*77 = 43.12.
So the option 3 answer matches with the option 3 in the question. The correct answer is option 3. i.e.. 42, 33.
Sneha said:
1 decade ago
He got 9 marks.
Kavi said:
1 decade ago
How come x+x+9?
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