Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 2)
2.
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
39, 30
41, 32
42, 33
43, 34
Answer: Option
Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56 (x + 9 + x)
100

25(x + 9) = 14(2x + 9)

3x = 99

x = 33

So, their marks are 42 and 33.

Discussion:
170 comments Page 11 of 17.

Shubham thakur said:   9 years ago
It's very simple.

If 1student got 56% that means other got 44%.
56 - 44 = 12%.
Fr 12%~9 is there,
So, for 100% ~99.

Only pair which satisfies it is 39 & 30.
That it.

Anirudh razdan said:   9 years ago
Why do we equate it to x + 9? Why not x?

Roja said:   9 years ago
Thank you @Ganesh.

Piyush Pankaj said:   9 years ago
Thanks @Neelu.

Karthikeyan said:   9 years ago
Can you please explain why we keep in x + 9 on the left side?

DURGAO said:   9 years ago
Thank you @ Radhika.

Santanu said:   9 years ago
56% - 44% = 9.
100% = 75.

Which total makes 75. That's it.

Satheeshkumar said:   9 years ago
How 25 came? Please explain that.

Archana Gaikwad said:   9 years ago
56% - 44 = 9.

But please explain 100% = 75.

& How 25 come?

Mohan said:   9 years ago
To my understanding.

Student 2 score = x.
Student 1 score 9 marks more than student 2 = x + 9 which is 56 percent of the total marks(x + x + 9) right.

x + 9 = 56%(x + x + 9).

Solving the above equation we will get x = 33 which is student 2 mark.

Student 1 has scored 9 marks more than student 2 so 33 + 9 = 42.


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