Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
96 comments Page 5 of 10.

Prince said:   7 years ago
But using the formula we get the answer is 4.137.

Ravi Kumar said:   6 years ago
Hello @Manish.

Total will be 100%
20% for rent.
60%for expenses.
10% for LIC.
TOTAL 90% OVER.
Know remaining spend 30.
10%=30 then 100%=300 total salary.

Satwika said:   9 years ago
Why should we take 17,5000 in denominator why not 26,25000?

Pallavi said:   6 years ago
Hi, I am not getting this. Please, someone, help me.

Nadeem said:   6 years ago
We use the formula 262500 = 175000(1+ R/100)^n.

Where n = 10, and the value of R turns out to be 4.138 which is 4.138%. So none of these is the answer.

Goku said:   5 years ago
@Aparna.

You are 100% wrong. Because you should take 60% of 100Rs, not 60% out of 80.

Take the % out of 100Rs, not out of remaining cost.

Venkatesh said:   5 years ago
Easy method:

Salary be x.

Total expenditure is 20%+60%+10% = 90%.
Remaining 10%,
10% of x = 30rs,
10x = 3000,
X = 300rs,
Salary is 300rs.

Muskan said:   4 years ago
Same here @Ankan Mondal.

Yoga said:   1 month ago
Why aren't we using the formula of P (1+R/100) ^N? Please explain to me.

Prakash singha said:   7 days ago
Nice, Thanks for explaining.


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