Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
93 comments Page 6 of 10.

Bluespark said:   1 decade ago
@ak123
%increase=(increase*100)/year its a formula since u r finding the increase % of 175000, yr=175000

Venkatesh said:   5 years ago
Easy method:

Salary be x.

Total expenditure is 20%+60%+10% = 90%.
Remaining 10%,
10% of x = 30rs,
10x = 3000,
X = 300rs,
Salary is 300rs.

Goku said:   5 years ago
@Aparna.

You are 100% wrong. Because you should take 60% of 100Rs, not 60% out of 80.

Take the % out of 100Rs, not out of remaining cost.

Nadeem said:   5 years ago
We use the formula 262500 = 175000(1+ R/100)^n.

Where n = 10, and the value of R turns out to be 4.138 which is 4.138%. So none of these is the answer.

Pallavi said:   5 years ago
Hi, I am not getting this. Please, someone, help me.

Mahi said:   1 decade ago
Why we use 10 here?

SamuelAA said:   10 years ago
If a number is 20% more than the other, how much percent is less than the first?

Can somebody solve this please?

Sneha said:   10 years ago
May be it is:

a-0.25 x = c.
b-0.20 x = c.

a-0.25 x = b-0.20 x.
a-0.45 x = b.
a is 45% greater than b.

Shashi said:   1 decade ago
Dear, @Anil.

What is the third number?

Saravanan said:   1 decade ago
How to say it's 10 years difference?


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