Aptitude - Percentage - Discussion

Hai @Sree.

First I assume your answer is correct, now 4.137% in first year means answer increase of 7240, now I 175000+7240= 182240(this value is the population up to 2nd year, now I add 4.137% of 18220..

This process is continued so that I will get the answer of the population at the end of 12th year,

But this the wrong of doing, here you are calculating the increase in percentage of the next year w.r.t to previous year (for example you are calculating the 3rd year increase in percentage of the population of 2nd year, this gives the result wrong as per our question, here in our question they asked the avg increase in % )...hope you understand.

Hi @Jayakumar s

let the total number of votes = x
no.of votes cast = 75% of x
The valid votes = 98% of (no.of votes cast)
i.e 98% of (75% of x) (here 2% is invalid so (100-2)%=98%)

Then (A candidate got 75% of valid votes =9261)
75% of (98% of (75% of x) = > 75/100 * 98/100 *75/100 * x =9261.
= > (9261*100*100*100) / (75*98*75),
= > 9261000000 / 551250,
= >16800.

@aparna you may be wrong becoz...

suppose his salary is x Rs.
then 20% of his x for rent=20/100*x = 20x/100...1
60% of his x for living expanses = 60x/100...2
10% of his x for LIC = 10x/100...3
30 Rs on education he spent

then we can write (20x/100)+(60x/100)+(10x/100)+30 = x
solve this you get x = 300
for check you put x value in all equations 1,2, 3 and add them with 30
you get total salary as 300

We can also solve with options.

A) 4.37 % 175000 = 7647.5.
So decade means 10 year.
multiply 10*7647.5= 76475.
and add the multiply result with the 175000.
i.e)76475+175000 =2514755% 17500.
So it's not matching.

B) 5% 175000 = 8750.
so decade means 10 year.
multiply 10*8750= 87500.
and add the multiply result with the 175000.
i.e)87500+175000 = 262500.

Its right so answer is B.

Ya vinay is right.

Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.

I think the official answer is wrong : if you increase a population of 175,000 by 5% each year during 10 years it becomes more than 262,500.

Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!

So it should be less than 5%.

Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.

So, A mus be the right choice.

@Udhaya Kumar:

Let's say that the number is 100.

Now increase in 29.7 % means.
100+29.7%100 = (100+29.7) = 129.7-----> (1).

Now the multiplier is 1.297. So multiply it to the assumed number i.e.
100*1.297=129.7-----> (2).

So from (1) & (2) the number increased by 29.7%.

Hope this helped.
Have a nice test !

Population in 2001 = 138915
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.

Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.

The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).

In an election between two candidates, 75% of the voter's caste their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.

Can anyone solve this?

@Rajesh.

The question says to find out the Avg. Percent of increase per year. 17500 is the initial population which the place had hence you can't take the increased population, ie, 263500 because you Have to find the increase only. So 175000 is the denominator.