Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
93 comments Page 1 of 10.
Nayana said:
5 years ago
Formula:
1 => Decrease = difference/high value*100.
2 => Increase = difference/low value *100.
Difference = 262500 - 175000 = 87500.
Lower value = 175000.
=> increase = 87500/175000 * 100 = 50
We need to find for per year so 50/10 = 5.
1 => Decrease = difference/high value*100.
2 => Increase = difference/low value *100.
Difference = 262500 - 175000 = 87500.
Lower value = 175000.
=> increase = 87500/175000 * 100 = 50
We need to find for per year so 50/10 = 5.
(31)
Priyanka said:
1 year ago
The population increased in 10 years 262500 - 175000 = 87500. For a decade that is for 10 years
Per year increase 87500/10= 8750.
Avg per cent increase in population per year= 8750/175000*100 = 5 per cent.
Per year increase 87500/10= 8750.
Avg per cent increase in population per year= 8750/175000*100 = 5 per cent.
(28)
Vikash Pal said:
2 years ago
It was mentioned increase was there in a decade means
we have a 50% increase in 10 years.
Now we were asked in 1 year =?
Simply unitary method
10 -> 50
1 -> ?
1*50/10 = 5%.
we have a 50% increase in 10 years.
Now we were asked in 1 year =?
Simply unitary method
10 -> 50
1 -> ?
1*50/10 = 5%.
(21)
Ali said:
3 years ago
Why not directly the formula of compound interest for finding population after nth years is not used?
Anyone, please clarify it.
Anyone, please clarify it.
(15)
T Muvetha said:
1 year ago
A decade means 10 years.
(13)
Sukumar Natarajan said:
3 years ago
Here, we have to use the formula P = (1+r/100) ^n.
So, the Answer is: 4.23%.
So, the Answer is: 4.23%.
(10)
Siddhant said:
10 months ago
262500 = x% of 175000
i.e. 150% of 175000
Thus, a 50% increase from 100%.
50% increase in 10 years, so 5% increase per year.
i.e. 150% of 175000
Thus, a 50% increase from 100%.
50% increase in 10 years, so 5% increase per year.
(7)
S A DEVIKA said:
2 years ago
We are taking 10 years since it has been mentioned in the question that there is an increase in a decade.
So, 1 decade = 10 years.
So, 1 decade = 10 years.
(7)
Sanjana said:
3 years ago
Yes, you are right @Nayan.
@Karankumar. We need to find it per year and so 50/10 =5 hear we divide 50 by 10 because they have given the word "decade" in the question which means 10 years. I hope you have understood. Thank you.
@Karankumar. We need to find it per year and so 50/10 =5 hear we divide 50 by 10 because they have given the word "decade" in the question which means 10 years. I hope you have understood. Thank you.
(6)
Ankan Mondal said:
4 years ago
Sir, I cannot understand. Anyone explain, please.
(4)
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