Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 10 of 10.
Shashi said:
1 decade ago
Dear, @Anil.
What is the third number?
What is the third number?
Saravanan said:
1 decade ago
How to say it's 10 years difference?
Anil said:
1 decade ago
Two numbers are respectively 25% and 20% more than of third. What percentage is the first of second. Could you solve this problem any one?
Aparna said:
1 decade ago
How 50/10 came in the last step. Can anyone help me to understand?
Dinesh said:
1 decade ago
Dear @Manisha you can solve that problem very simply.
Add all the expenses so 20+60+10 = 90.
Out of 100% 90% spending on his expenses so 100-90 = 10.
Let the salary be x.
10% of x = 30.
10/100*x = 30 we get.
1/10*x = 30.
So x = 300.
Add all the expenses so 20+60+10 = 90.
Out of 100% 90% spending on his expenses so 100-90 = 10.
Let the salary be x.
10% of x = 30.
10/100*x = 30 we get.
1/10*x = 30.
So x = 300.
Yatender said:
1 decade ago
Most of them are wrong because firstly we use our original salary then 20%of that salary=remaining and 60% of that remaining and so on. @Aparna is right.
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