Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
93 comments Page 10 of 10.
AgentSteel said:
9 years ago
20 + 60 + 10 = 90%,
Rem 10% = 30,
Therefore, total salary = 300.
Rem 10% = 30,
Therefore, total salary = 300.
Shivaranjitha said:
9 years ago
Maybe, if the 3rd no = 100.
Then 1st no is 25% more than that = 125.
In the same way 2nd no=120.
Now the question is 125 is What % of 120.
So it would be (125/120) *100.
Approximately equal to 104.
Then 1st no is 25% more than that = 125.
In the same way 2nd no=120.
Now the question is 125 is What % of 120.
So it would be (125/120) *100.
Approximately equal to 104.
Ashok said:
9 years ago
@Manisha.
10% = 30rs(given).
Then,
20% = 60rs (30 * 2 = 60, 10 * 2 = 20%).
Similarly;
60% = 180rs,
10% = 30rs,
Add all gives 100% = 300rs.
10% = 30rs(given).
Then,
20% = 60rs (30 * 2 = 60, 10 * 2 = 20%).
Similarly;
60% = 180rs,
10% = 30rs,
Add all gives 100% = 300rs.
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