Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
96 comments Page 9 of 10.

Keshav said:   9 years ago
@Aparna,

20% + 60% + 10% = 90%.

Means rest 10% = 30 rupee.

So obviously his salary will be 300 (100%).

Mathu said:   9 years ago
Why we can't use 262500. To divide the number 87500.

Swathi said:   9 years ago
@Rajesh.

The question says to find out the Avg. Percent of increase per year. 17500 is the initial population which the place had hence you can't take the increased population, ie, 263500 because you Have to find the increase only. So 175000 is the denominator.

Rajesh said:   10 years ago
Why 175000 is taken in the denominator instead of taking 2,62,500?

AgentSteel said:   10 years ago
20 + 60 + 10 = 90%,

Rem 10% = 30,

Therefore, total salary = 300.

Arisha said:   9 years ago
How (50/10)%?

Ashok said:   10 years ago
@Manisha.

10% = 30rs(given).

Then,
20% = 60rs (30 * 2 = 60, 10 * 2 = 20%).

Similarly;

60% = 180rs,
10% = 30rs,

Add all gives 100% = 300rs.

Vikrala said:   10 years ago
There's a shortcut here i.e 100*r/100+r = 100*20/100+20.

You can easily get the result.

SamuelAA said:   1 decade ago
If a number is 20% more than the other, how much percent is less than the first?

Can somebody solve this please?

Sneha said:   1 decade ago
May be it is:

a-0.25 x = c.
b-0.20 x = c.

a-0.25 x = b-0.20 x.
a-0.45 x = b.
a is 45% greater than b.


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