Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
93 comments Page 8 of 10.

Rajesh said:   1 decade ago
Hai @Sree.

First I assume your answer is correct, now 4.137% in first year means answer increase of 7240, now I 175000+7240= 182240(this value is the population up to 2nd year, now I add 4.137% of 18220..

This process is continued so that I will get the answer of the population at the end of 12th year,

But this the wrong of doing, here you are calculating the increase in percentage of the next year w.r.t to previous year (for example you are calculating the 3rd year increase in percentage of the population of 2nd year, this gives the result wrong as per our question, here in our question they asked the avg increase in % )...hope you understand.

Sree said:   1 decade ago
How far the answer 5% is correct.

(50/10)% is OK but on back_end process the value(262500) cannot satisfy 175000.

If 4.137% suits for it.

CAN ANYONE UNDERSTOOD?

CAN ANYONE HEAR TO CLEAR MY DOUBT?

Sheshu said:   1 decade ago
%increase=difference/lowvalue*100.

%decrease=difference/highvalue*100.

Prasad. said:   1 decade ago
Easy method to find the salary of the person.
20% on rent+60%on living +10% on L.I.C.+ remain 30rs on children.
20%+60%+10%+30rs=100%.
90% spent remain 30rs is equal to 10%. (.i.e 100%-90%=10%)
if 10 % =30rs ==> 100%=300 Rs.

Angelo said:   9 years ago
What is the answer, if the population of the town is increased by 5% annually. If its population in 2001 was 138915. Then What was it in 1998?

Please anyone solve this.

Jayakumar s said:   8 years ago
In an election between two candidates, 75% of the voter's caste their votes, out of which 2% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. Find the total number of votes enrolled in that election.

Can anyone solve this?

Krishnam raju said:   9 years ago
percentage increase = (increased quantity/initial quantity) * 100.

As given above problem.

Increased quantity = 262500 - 17500.
= 87500
Percentage increase = (87500/175000) * 100.
= 50% per decade means for 10 years.

Per one year = 50/10 = 5%.

Anil said:   9 years ago
Population in 2001 = 138915
Population in 1998 was = 138915 * 100/105 * 100/105 * 100/105 = 1,20,000.

Had it given the population in 1998 = 1,20,000 then what will be the population in 2001, if it increases @5% PA.

The solution would be = 1,20,000 * 105/100 * 105/100 * 105/100 = 138915 (population in 2001).

Arisha said:   9 years ago
How (50/10)%?

Shru said:   9 years ago
Guys it's very simple, here they used the formula for % change that is =difference in % ÷ initial value * 100.


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