Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
97 comments Page 8 of 10.
Vishnu said:
2 decades ago
Ya vinay is right.
Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.
Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.
Rahul said:
2 decades ago
@vijay.
Ya you are right vijay. Watt aparna did is wrong.
Ya you are right vijay. Watt aparna did is wrong.
Vijay said:
2 decades ago
@aparna you may be wrong becoz...
suppose his salary is x Rs.
then 20% of his x for rent=20/100*x = 20x/100...1
60% of his x for living expanses = 60x/100...2
10% of his x for LIC = 10x/100...3
30 Rs on education he spent
then we can write (20x/100)+(60x/100)+(10x/100)+30 = x
solve this you get x = 300
for check you put x value in all equations 1,2, 3 and add them with 30
you get total salary as 300
suppose his salary is x Rs.
then 20% of his x for rent=20/100*x = 20x/100...1
60% of his x for living expanses = 60x/100...2
10% of his x for LIC = 10x/100...3
30 Rs on education he spent
then we can write (20x/100)+(60x/100)+(10x/100)+30 = x
solve this you get x = 300
for check you put x value in all equations 1,2, 3 and add them with 30
you get total salary as 300
Aparna said:
2 decades ago
@manisha
suppose his salary is Rs.100
20% of 100=20
100-20=80
60% of 80=48
80-48=32
10% of 32=3.2
32-3.2=28.8
hence
28.8 = 30
100 =?
we get
104.16
hence his salary is Rs.104.16
suppose his salary is Rs.100
20% of 100=20
100-20=80
60% of 80=48
80-48=32
10% of 32=3.2
32-3.2=28.8
hence
28.8 = 30
100 =?
we get
104.16
hence his salary is Rs.104.16
Shivaranjitha said:
1 decade ago
Maybe, if the 3rd no = 100.
Then 1st no is 25% more than that = 125.
In the same way 2nd no=120.
Now the question is 125 is What % of 120.
So it would be (125/120) *100.
Approximately equal to 104.
Then 1st no is 25% more than that = 125.
In the same way 2nd no=120.
Now the question is 125 is What % of 120.
So it would be (125/120) *100.
Approximately equal to 104.
Shru said:
10 years ago
Guys it's very simple, here they used the formula for % change that is =difference in % ÷ initial value * 100.
Mohsin said:
10 years ago
10% is equal to 30.
While 100% is equal to?
Then,
30 * 100/10 = 300.
While 100% is equal to?
Then,
30 * 100/10 = 300.
Surya said:
10 years ago
Decade means?
Sreekanth said:
10 years ago
Anyone explain how 50/10?
Angelo said:
10 years ago
What is the answer, if the population of the town is increased by 5% annually. If its population in 2001 was 138915. Then What was it in 1998?
Please anyone solve this.
Please anyone solve this.
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