Aptitude - Percentage - Discussion

Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Answer: Option
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% = 87500 x 100 % = 50%.
175000

Required average = 50 % = 5%.
10

Discussion:
96 comments Page 2 of 10.

Ankan Mondal said:   4 years ago
Sir, I cannot understand. Anyone explain, please.
(4)

Karunakar said:   4 years ago
How do you know for taking the 10 years? Please explain me.
(4)

Naveen Kumar said:   4 years ago
100-(20+60+10) = 10%.
10% = 30 means 100% = 300.
(2)

Ann said:   9 years ago
I think the official answer is wrong : if you increase a population of 175,000 by 5% each year during 10 years it becomes more than 262,500.

Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!

So it should be less than 5%.

Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.

So, A mus be the right choice.
(2)

Captain said:   5 years ago
@Manisha it is very easy.

20% rent
60%expenses
10% lic
30rs children education.

So 20+60+10=90%
The remaining 10% is left which is for education.
So 10% means 30 rs.
For 100%=300 rs.
So answer will be 300.
(2)

Yoga said:   3 months ago
Why aren't we using the formula of P (1+R/100) ^N? Please explain to me.
(2)

Prashant said:   2 months ago
Anyone, explain me, why we are not using compounding? Please clarify it.
(2)

Ajit Raj said:   7 years ago
@Manisha.

Take total salary = 100%.
100% - 20% - 60% - 10%,
= 10%.

According to the question:
10%= 30, then,
100%=x,
By cross multiplication, we got x= 300.
Which was his total salary.
(1)

Ganeshvictory said:   7 years ago
1 decade = 10 years.

Population increased as 175000 to 262000 in decade;
x = (262000-175000) = 87500.
increase percentage =(x/175000*100) = 50%.
The required average of decade from increased percentage = [increased percentage / decade] = (50/10)% = 5%.
(1)

Riad said:   6 years ago
Suppose,
Salary = x.

(100-90)% of x = 30.
10/100 * x = 30.
x = 30*100/10.
x = 300.
(1)


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