Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
96 comments Page 2 of 10.
Prashant said:
5 months ago
Anyone, explain me, why we are not using compounding? Please clarify it.
(4)
Ankan Mondal said:
5 years ago
Sir, I cannot understand. Anyone explain, please.
(4)
Karunakar said:
5 years ago
How do you know for taking the 10 years? Please explain me.
(4)
Prakash singha said:
5 months ago
Nice, Thanks for explaining.
(3)
Yoga said:
6 months ago
Why aren't we using the formula of P (1+R/100) ^N? Please explain to me.
(3)
Naveen Kumar said:
4 years ago
100-(20+60+10) = 10%.
10% = 30 means 100% = 300.
10% = 30 means 100% = 300.
(2)
Captain said:
6 years ago
@Manisha it is very easy.
20% rent
60%expenses
10% lic
30rs children education.
So 20+60+10=90%
The remaining 10% is left which is for education.
So 10% means 30 rs.
For 100%=300 rs.
So answer will be 300.
20% rent
60%expenses
10% lic
30rs children education.
So 20+60+10=90%
The remaining 10% is left which is for education.
So 10% means 30 rs.
For 100%=300 rs.
So answer will be 300.
(2)
Ann said:
10 years ago
I think the official answer is wrong : if you increase a population of 175,000 by 5% each year during 10 years it becomes more than 262,500.
Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!
So it should be less than 5%.
Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.
So, A mus be the right choice.
Proof 175,000 * (1.05 ^ 10) = 285'056.56 that's more then 262,500!
So it should be less than 5%.
Right answer : ( (262,500/175,000) ^ 0.1) - 1 = 4.137974%.
So, A mus be the right choice.
(2)
Bhavna said:
1 decade ago
Thanks shivani.
(1)
Pavan said:
1 decade ago
Nice Muthupazhani.
(1)
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