Aptitude - Percentage - Discussion
Discussion Forum : Percentage - General Questions (Q.No. 15)
15.
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
| Increase% = |  |
87500 | x 100 |  % = 50%. |
| 175000 |
 Required average = |
|
50 | % = 5%. |
| 10 |
Discussion:
93 comments Page 4 of 10.
Saiswarupa said:
7 years ago
Thank you @Nikhil Dasari.
Lopamudra said:
8 years ago
Suppose man's salary =100 Rs.
20%=20 Rs rent,
60% =60 Rs Expense,
10% =10 Rs LIc,
so left amount for education=100-(20+60+10)=10,
10% left ie 10 Rs of 100 %,
10%= 30(In qs),
1% =30/10,
100% =30*100/10=300(salary).
20%=20 Rs rent,
60% =60 Rs Expense,
10% =10 Rs LIc,
so left amount for education=100-(20+60+10)=10,
10% left ie 10 Rs of 100 %,
10%= 30(In qs),
1% =30/10,
100% =30*100/10=300(salary).
Anil said:
8 years ago
Why we divided 50 by 10?
Mr. bhatiya said:
8 years ago
Good @Shivani.
Nikhil dasari said:
8 years ago
We can also solve with options.
A) 4.37 % 175000 = 7647.5.
So decade means 10 year.
multiply 10*7647.5= 76475.
and add the multiply result with the 175000.
i.e)76475+175000 =2514755% 17500.
So it's not matching.
B) 5% 175000 = 8750.
so decade means 10 year.
multiply 10*8750= 87500.
and add the multiply result with the 175000.
i.e)87500+175000 = 262500.
Its right so answer is B.
A) 4.37 % 175000 = 7647.5.
So decade means 10 year.
multiply 10*7647.5= 76475.
and add the multiply result with the 175000.
i.e)76475+175000 =2514755% 17500.
So it's not matching.
B) 5% 175000 = 8750.
so decade means 10 year.
multiply 10*8750= 87500.
and add the multiply result with the 175000.
i.e)87500+175000 = 262500.
Its right so answer is B.
Suman said:
1 decade ago
Thanku Naren you gave a very shortcut method.
Aparna said:
1 decade ago
@manisha
suppose his salary is Rs.100
20% of 100=20
100-20=80
60% of 80=48
80-48=32
10% of 32=3.2
32-3.2=28.8
hence
28.8 = 30
100 =?
we get
104.16
hence his salary is Rs.104.16
suppose his salary is Rs.100
20% of 100=20
100-20=80
60% of 80=48
80-48=32
10% of 32=3.2
32-3.2=28.8
hence
28.8 = 30
100 =?
we get
104.16
hence his salary is Rs.104.16
Vijay said:
1 decade ago
@aparna you may be wrong becoz...
suppose his salary is x Rs.
then 20% of his x for rent=20/100*x = 20x/100...1
60% of his x for living expanses = 60x/100...2
10% of his x for LIC = 10x/100...3
30 Rs on education he spent
then we can write (20x/100)+(60x/100)+(10x/100)+30 = x
solve this you get x = 300
for check you put x value in all equations 1,2, 3 and add them with 30
you get total salary as 300
suppose his salary is x Rs.
then 20% of his x for rent=20/100*x = 20x/100...1
60% of his x for living expanses = 60x/100...2
10% of his x for LIC = 10x/100...3
30 Rs on education he spent
then we can write (20x/100)+(60x/100)+(10x/100)+30 = x
solve this you get x = 300
for check you put x value in all equations 1,2, 3 and add them with 30
you get total salary as 300
Rahul said:
1 decade ago
@vijay.
Ya you are right vijay. Watt aparna did is wrong.
Ya you are right vijay. Watt aparna did is wrong.
Vishnu said:
1 decade ago
Ya vinay is right.
Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.
Let his salary is x. let us consider only expenses (20/100)*x+(60/100)*x+(10/100)*x are expenses.
in problem it given that if we subtract all expenses from salary,he remained with 30rs which used for education so,
x-((20/100)*x+(60/100)*x+(10/100)*x)=30
(100x-(20x+60x+10x))/100=30
100x-90x=3000
10x=3000
x=300
so vijay is right.......of course me tooooo.
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