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Aptitude - Numbers - Discussion

Discussion Forum : Numbers - General Questions (Q.No. 4)
Numbers
4.
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
2
3
18
21
None of these
Answer: Option
Explanation:
 23) 1056 (45
      92
      ---
      136
      115
      ---
       21
      ---
     
 Required number = (23 - 21)    
                 = 2.
Discussion:
73 comments Page 4 of 8.
Adithya said:   8 years ago
Hi Guys, it is simple first calculate 23*46 = 1058, Then see our number it is 1056, So to get remainder as Zero we need to add 2.
Astik said:   8 years ago
1056/23.

=23/1056/46
92
-----------
136
138
-------------


When we multiply 23*5=115.
2
But I take one 1 more bigger digit I multiply 23*6=138
Difference of this two numbers is 2.
This is the simplest way.
Nkumar said:   8 years ago
1056+2=1058, it is completely divided by 23, so difference no. 1056-1058 =2, because 1058/23 =46.
Ankur said:   8 years ago
@Nandi.

Please apply same formula in 1045 instead of 1056, 23 will remain same.
Sathish said:   8 years ago
Why we did 23-21?
Satish chandra said:   7 years ago
When 1056 divided by 23 it yields 21 but we need to get "0" as remainder if we add +2 to 21 (i.e. 1058 it gives 23 as the remainder when it gets divided by 23) and it 23 get divided by 23 yields zero "0".
Soura said:   7 years ago
@Mohanagiri.

Smart approach, Thanks.
Muthu said:   7 years ago
@ALL.

As per my method.

10 * 23 = 2300
2300/2 = 1150
1150-1056 = 94
94/23 = 4 quotient balance 2 ans is 2.
Suba said:   1 decade ago
23x45=1035 so 1056-1035=21 so the number 23-21=2 this is the answer
Roshinphilips said:   1 decade ago
1056/23 = 45.xx,

45*23 = 1035,

1035+23 = 1058.

Difference between 1056 and 1058 = 2.
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